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3 years ago

Justin has 34 quart of cranberry. if you divide the juice into glasses that hold 18 quart how many classes can justin fill?

Mathematics

1 answer:

Zina [86]3 years ago

3 0

34/18 = 1.8.....so he can fill 1 glass full...with 16 qts left over

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80 Hundreds = ____ Thousandths

allsm [11]

The answer would be 0.8, because 800 hundreds go into 8 thousandths, but there is only 80 hundreds, so the answer is 0.8 thousandths.
Answer: 0.8 thousandths

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3 years ago

Given the venn diagram, find P(brother and sister)

LUCKY_DIMON [66]

Based on the venn diagram of siblings, the probability of having a brother and sister is c. 0.33.

<h3>What is the probability of brother and sister?</h3>

The probability of having a brother and sister can be found as:

= Number of those with brother and sister / Total number of people in poll

Solving gives:

= 10 / (8 + 10 + 5 + 7)

= 10 / 30

= 0.33

In conclusion, the probability of having a brother and sister is 0.33.

Find out more on Venn diagrams at brainly.com/question/9085273

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2 years ago

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NeTakaya

Answer:

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Step-by-step explanation:

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3 years ago

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Nadusha1986 [10]

Answer:

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3 years ago

Read 2 more answers

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago