All categories

2 years ago

Factorise 4ab +6bn-2a-3n

Mathematics

2 answers:

Lesechka [4]2 years ago

7 0

Answer:

(2b - 1)(2a + 3n)

-----------------------------------------------

Given polynomial

4ab + 6bn - 2a - 3n

Factorize it as below:

4ab + 6bn - 2a - 3n =

(4ab - 2a) + (6bn - 3n) = Regroup

2a(2b - 1) + 3n(2b - 1) = Factorize each group using common factors

(2b - 1)(2a + 3n) Factorize using common factor

Lady_Fox [76]2 years ago

4 0

Answer:

$(2b-1)(2a+3n)$

Step-by-step explanation:

Given expression:

$4ab+6bn-2a-3n$

Factorize the first two terms and the last two terms separately:

$\implies 2b(2a+3n)-1(2a+3n)$

Factor out the common term (2a + 3n):

$\implies (2b-1)(2a+3n)$

You might be interested in

Alyssa is driving to Chicago, and she is traveling at 60 miles per hour. If Chicago is 96 miles away, how long will it take her

Leviafan [203]

Answer: C

Step-by-step explanation: 1hour 36minutea

8 0

3 years ago

Read 2 more answers

Points A and B are on the different sides of a line 1, the distance between point A and the line lis 10 in, the distance between

givi [52]

Answer: Distance between O and the line 1 is 3 inches.

Explanation:

Since we have given that

Distance between point A and the line 1 = 10 inches

Distance between point B and the line 1 = 4 inches

Total length of segment AB is given by

$10+4=14\ inches$

Since O is midpoint of the line segment AB.

so, AO is given by

$\frac{14}{2}=7\ in.$

Now, Distance between O and the line 1 is given by

$10-7=3\ in.$

Hence, Distance between O and the line 1 is 3 inches.

7 0

3 years ago

Question 3 Solve for m. 4 over 3 m equals 4

Lorico [155]

Answer:

$m = 3$

Step-by-step explanation:

$\frac{4}{3} m = 4 \\ divide \: both \: sides \: by \: \frac{4}{3} \\ \\ m = 3$

3 0

3 years ago

I need help babnwnwnnw

hoa [83]

I agree the answer is B I think so

4 0

2 years ago

The height h(n) of a bouncing ball is an exponential function of the number n of bounces.

Digiron [165]

Answer:

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

$h = h_{o}\cdot r^{n-1}$ , $n \in \mathbb{N}$ , $0 < r < 1$ (1)

Where:

$h_{o}$ - Height reached by the ball on the first bounce, measured in feet.

$r$ - Decrease rate, no unit.

$n$ - Number of bounces, no unit.

$h$ - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

$r = \frac{h_{1}}{h_{o}}$ (2)

Where $h_{1}$ is the height reached by the ball on the second bounce, measured in feet.

If we know that $h_{o} = 6\,ft$ and $h_{1} = 4\,ft$ , then the expression for the height of the bouncing ball is:

$h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

5 0

2 years ago

Read 2 more answers

Factorise 4ab +6bn-2a-3n​

Factorise 4ab +6bn-2a-3n