It is normally smart to write out a diagram of some sort to help you visualize the situation. I made one for this situation, although it might now suit you as well as it would me.
The idea behind this problem is to make you understand rates. Rates being the same thing as a slope. If you have learned about that already then that will help a lot, but if you haven't then that's fine.
So we have 4.8m and we traveled at a speed of 3 meters per 1 minute. A rate you are probably pretty familiar with is mph. Which is Miles per Hour. Or if you don't live in the U.S. Kmph. Which is Kilometers per Hour.
What you do to solve these type of problems is you take the given value and you use the rate to get the value you want.
The easiest way to do this is to make sure the signs (Meters) "cancel" out.
4.8m * (1min / 3m)
To cancel something out you need to have it over itself. Here are a few examples:
3/3 = 1
4/4 = 1
100,000/100,000 = 1
598/598 = 1
In the case of units, such as meters. They go *poof* from the problem.
So we have this problem:
(4.8m*1 minute) / 3m = ? minutes
4.8/3 = 1.6
If you want the answer in fractional form... here is how you do it: (I won't explain it because you most likely won't need to do this, but if you want to know how to do it then just ask)
4(8/10)
4(4/5)
(24/5)/3
(24/5) * (1/3)
24/15
8/5 is our final fractional answer!
Answer:
The z-score for an income of $2,100 is 1.
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
Given:
µ = $2,000
σ = $100
<em>x</em> = $2,100
Compute the <em>z</em>-score for the raw score <em>x</em> = 2100 as follows:

Thus, the z-score for an income of $2,100 is 1.
Answer:
=11600/3
=3866.66kg
Step-by-step explanation:
dividing the mass with bricks with the three times of the lorry
Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
x=-10
Step-by-step explanation:
2(x+3)=x-4 (Multiply the 2 by the x and the 3);
2x+6=x-4 (Now you group like terms)
2x-x=-4-6
x=-10