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marusya05 [52]
3 years ago
15

What is the probability of flipping two coins at the same time and getting heads on both coins?

Mathematics
2 answers:
inysia [295]3 years ago
8 0

Answer:

Where is the minimum number of coins that must be reserved?

Step-by-step explanation:

Romashka-Z-Leto [24]3 years ago
5 0
According to me the probability is 1/4, because there are 4 possible outcomes when two coins are flipped - TT, TH, HT, HH. 

<span>Also, would it matter if the coins are flipped one after other rather than together</span>
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The answer is 8 because if you divide 52 by 4 it gives 13, do the same to the top and you get 8

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Few students manage to complete their schooling without taking a standardized admissions test such as the Scholastic Achievement
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Answer:

Step-by-step explanation:

Assuming there is a punitive removal of one point for an incorrect response.

Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60

Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50

I'll use 0.33 as an approzimation for 1/3

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And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.

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6 0
3 years ago
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just olya [345]

Answer:

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nadezda [96]
<h2>\large\mathfrak{{\pmb{\underline{\red{Given}}{\red{:}}}}}</h2>
  • ∠RSU and ∠USV are complementary angles
  • ∠RSU = (4x – 15)°
  • ∠USV = 20°

<h2>\large\mathfrak{{\pmb{\underline{\color{red}{To~find}}{\color{red}{:}}}}}</h2>
  • The value of x

<h2>\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}</h2>
  • ∠RSU and ∠USV are complementary angles

\sf\implies{ \angle RSU + \angle USV = 90 \degree }

\sf\implies{ (4x-15) + 20 = 90 }

\sf\implies{ 4x-15+20=90}

\sf\implies{4x+5=90}

\sf\implies{4x=90-5}

\sf\implies{4x=85}

\sf\implies{x={\dfrac{85}{4}}}

\sf\implies{ {\orange{\underline{\boxed{\sf{\pmb{x=21.25}}}}}}}

<h2>\large\mathfrak{\therefore{\pmb{\underline{\color{gold}{Required~answer}}{\color{gold}{:}}}}}</h2>
  • \sf{ {\underline{\underline{\color{gold}{\sf{\pmb{x=21.25}}}}}}}
5 0
3 years ago
Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


6 0
3 years ago
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