2 years ago

1.10/11+4/5 2.1/5+1/6

Mathematics

1 answer:

8_murik_8 [283]2 years ago

7 0

(Answer)

1.)9

__. (0.9)

2.)44

__. (0.586)

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Find the value of n that satisfies 2(n+1)! + 6n! = 3(n+1), where $n! = n\cdot (n-1)\cdot (n-2) \cdots 2\cdot 1$.

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$n = 5$

Step-by-step explanation:

Given

$2(n+1)! + 6n! = 3(n+1)!$

Required

Find n

Simplify (n + 1)!

$2(n+1)*n! + 6n! = 3(n+1)*n!$

Factorize

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Divide both sides by n!

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Open brackets

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