Jade bike wheels have diameter of 20 inches how far does she travel if the wheel rotate 37 times

First you to find the worksheet and download it<br> plase I need help

Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = $3^{x + 2}$

The asymptote is given as x → -∞, f(x) = $3^{x + 2}$ → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = $3^{0 + 2}$ = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = $5^{1 - x}$

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = $5^{1 - 0}$ = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = $2^{x + 3}$ - 1

The asymptote is $2^{x + 3}$ → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) = $2^{0 + 3}$ - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, $2^{x + 3}$ - 1 = 0

$2^{x + 3}$ = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) $f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2$

The asymptote is $\left (\dfrac{1}{2} \right)^{x - 2}$ → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = $f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6$

The y-intercept is (0, 6)

7 0

2 years ago

Let D be the event that a randomly chosen person has seen a dermatologist. Let S be the event that a randomly chosen person has

SSSSS [86.1K]

Given:

D be the event that a randomly chosen person has seen a dermatologist.

S be the event that a randomly chosen person has had surgery for skin cancer.

To find:

The correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist.

Solution:

Conditional probability: Probability of A given B is:

$P(A|B)=\dfrac{P(A\cap B)}{P(B)}$

Let D be the event that a randomly chosen person has seen a dermatologist.

Let S be the event that a randomly chosen person has had surgery for skin cancer.

Using the conditional probability, the correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist is P(S|D).

Therefore, the correct option is D.

8 0

2 years ago

Sound travels about 335 meters/second. How many kilometers would a sound travel in 1 minute?

Lelechka [254]

If sounds travel 335 meters in 1 second , in 1 minute it travels 60 times that distance :

335m × 60 = 20100 meters
Sounds travel 20100 meters per minute
if 1000 meters = 1 km ,
20100 meters = 20100/1000 km
20100 meters = 20.1 Km

Awnser : Sound would travel 20.1 km in one minute

7 0

3 years ago

I need this solved ASAP please<br> ratio 4:12 simplified.

saveliy_v [14]

I’m not 100% certain but i’m pretty sure 1:3 works

5 0

3 years ago

Read 2 more answers

Justin walked 3 miles north and 6 miles west. starting from the same point, tina walked 2 miles south and 4 miles east. how far

Darya [45]

Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
Justin walked 3 miles north and 6 miles west so his distance from the start is the square root of 9+36 or 45. This can be simplified to 3√5.
Tina walked 2 miles south and 4 miles east so her distance from the starting point is the square root of 4 + 16 or 20. This can be written as 2√5.
If we add these two distances together we get 5√5. Hence, Justin and Tina are 5√5 miles away from each other.

6 0

3 years ago