Question

A recessive gene located on the X chromosome is the cause of one type of colorblindness (denoted by Xc). Let the genotype for normal vision be denoted by X+. Suppose a mother with normal vision (X+Xc) and a father with normal vision (X+Y) reproduce. Their child's possible genotypes can be illustrated with the following Punnett square. Punnett square If they have a daughter, her chance of having this type of colorblindness is %.

Answer 1

The scenario will be Son: 25% colorblind daughter: 25% colorblind son: 25% of carrier daughters with normal vision: 25% normal son

What is color blindness?

The condition is frequently inherited. Certain eye diseases and medications are also possible causes. Men are more affected than women.

Color blindness is characterized by the inability to distinguish between red and green shades.

A colorblind man's genotype is XcY, and a heterozygous carrier female's genotype is XcX. A cross between XcY and XcX would result in progeny with the following ratio=

Son: 25% colorblind daughter: 25% colorblind son: 25% of carrier daughters with normal vision: 25% normal son.

Thus, the couple is likely to have a son who is half normal and half affected. Similarly, the couple is likely to have 50% normal daughters and 50% colorblind daughters.

For more details regarding color blindness, visit:

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