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ella [17]
2 years ago
10

PLESE HELP ILL GIVE BRAINLIEST!,!!!!!

Mathematics
2 answers:
Bogdan [553]2 years ago
5 0

Answer:

9.8x + 1.1y + 9.9z

Step-by-step explanation:

\textsf {The perimeter is the sum of the side lengths.}

\textsf {Hence, the perimeter is :}

⇒ 5.5x + 6.2y + 4.3x + 8.3z + 1.6z - 5.1y

⇒ 9.8x + 1.1y + 9.9z

Tasya [4]2 years ago
5 0
Answer: C) 9.8x + 1.1y + 9.9z

Step-by-Step Explanation:

Perimeter = Side + Side + Side

Therefore,
= 5.5x + 6.2y + 4.3x + 8.3z + 1.6z - 5.1y
= (5.5 + 4.3)x + (6.2 - 5.1)y + (8.3 + 1.6)z
= 9.8x + (6.2 - 5.1)y + (8.3 + 1.6)z
= 9.8x + 1.1y + (8.3 + 1.6)z
=> 9.8x + 1.1y + 9.9z

Perimeter = 9.8x + 1.1y + 9.9z cm
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Step-by-step explanation:

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slava [35]

Answer:

401

Step-by-step explanation:

1. Approach

To solve this problem, one first has to think about the given figure in a certain way. In the figure, one can see that it is a circle attached on either side of a rectangle. To find the perimeter of the figure, one has to find the circumference of the circle and then add two sides of the rectangle to the answer

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Normally to find the circumference of a semicircle, one would have to divide this formula by 2, but since in this case, one has to add two congruent semicircles, so therefore, the effect of dividing the equation by two, only to multiply by two again cancels, and hence, there is no need to divide by 2.

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(78)(pi)

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skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

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