Answer:
3.4 x 107
Step-by-step explanation:
The height of the antenna on the roof of the local building is approximately 8 meters.
The situation forms a right angle triangle.
<h3>Properties of a right angle triangle:</h3>
- One of its angles is equals to 90 degrees
- The sides of the triangles can be calculated using Pythagoras theorem.
Therefore, let's find the height of the building and the radio antenna from the eye point.
Using trigonometric ratios,
tan 40° = opposite / adjacent
tan 40° = x / 25
where
x = the height of the building and the radio antenna from the eye point.
x = 25 tan 40
x = 25 × 0.83909963117
x = 20.9774907794 meters
Let's find the height of the building from his eye point.
tan 28° = y / 25
where
y = height of the building from his eye point
y = 25 × tan 28°
y = 25 × 0.53170943166
y = 13.2927357915 meters
Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786
Height of the antenna ≈ 8 meters
learn more on elevation here: brainly.com/question/17582385?referrer=searchResults
Answer:
The volume per dose that the patient should receive is 3.8 ml
Step-by-step explanation:
The physician ordered oncovin 2 mg/m² for chemotherapy treatment of a malignant tumor.
The adult's BSA (Body surface area) = 1.9m²
Hence, the amount of oncovin needed based on his body weight is:
2mg/1 m² = x mg/1.9m²
Cross Multiply
x mg = 2mg × 1.9
x = 3.8mg
We are told , oncovin is supplied:1 mg/ml
Hence:
This means
1 mg = 1 ml
3.8 mg = x ml
Cross Multiply
x ml = 3.8 ml
The volume per dose that the patient should receive is 3.8 ml
