Question

If a and b are negative real numbers and a

Answer 1

Answer:

$a^{2} > b^{2}$

Step-by-step explanation:

if  a<b<0

then the absolute value for a is greater than that of b

as a results, the square of a should be greater than that of b

Answer 2

Step-by-step explanation:

remember,

e.g. -12 < -8

or -741 < -589

but then the corresponding positive numbers

12 > 8

741 > 589

so, if we have 2 negative numbers a, b with a < b, then

a² > b²

because the square is always delivering a positive number.

and as positive a > positive b, then so is a² > b².