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Ronch [10]
2 years ago
7

Find the area of the shape below. All measurements are in miles.

Mathematics
1 answer:
IrinaK [193]2 years ago
6 0
731.04!! You multiply all together!! Mark me brainliest ?
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Find the missing value given (-1,7)(-3,d) m= 6 HELP ASAP WILL MAKE BRAINLEST
-Dominant- [34]

Answer:

d= -5

Step-by-step explanation:

The slope of a line is found by finding the ratio of change is y values to change is x values

m=y_2-y_1/x_2-x_1

The points on the line have coordinates at: (-1,7) (-3,d)

where ;

y_2=d, y_1=7,x_2=-3,x_1=-1,m=6

Applying the formula with values as;

6=\frac{d-7}{-3--1} \\\\6=\frac{d-7}{-3+1} \\\\6=\frac{d-7}{-2} \\\\6*-2=d-7\\\\-12=d-7\\\\-12+7=d\\\\-5=d

The value of d = -5

The coordinates of the points  (-1,7) (-3,-5)

6 0
3 years ago
4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep
bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.92}{2} = 0.04

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.04 = 0.96, so Z = 1.88.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that \sigma = 2.2

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.88\frac{2.2}{\sqrt{n}}

\sqrt{n} = 1.88*2.2

(\sqrt{n})^2 = (1.88*2.2)^2

n = 17.1

Rounding up:

A sample of 18 is required.

3 0
3 years ago
This one is confusing (slope)
Komok [63]

The answer is positive 1/5. Here is a tip, when reading a graph read from left to right. If it is going up to the right it is positive. If it goes down going to the right it is negative. Also think rise/run. Count how many times it goes up(or down) then count how long the line goes.

5 0
3 years ago
I NEED HELP ASAP. PLEASE TELL ME WHERE I WOULD GRAPH AND WHERE I WOULD SHADE. ALSO IF THE LINE WOULD BE SOLID OR NOT. 20 POINTS
luda_lava [24]

The first one is a dashed line and the second one is solid. Two points for the first one is (1,4) and (0,3). For the second one two points are (0,-3) and (1,0). From build the lines. Finally the first one is where y is greater so shade above the line with points like ( 10,10) or (7,8) in the shaded region. For the second one since y is less or equal to shade below the line with points like (-2,-10) or (-1,-5).

3 0
3 years ago
If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.
Triss [41]
(6y - 11)(6y + 11) = ay² - b    |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b    |add b to both sides

ay² = 36y² - 121 + b        |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

\boxed{a=\dfrac{36y^2-121+b}{y^2}}
7 0
3 years ago
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