Complete the following sentences to compare the two functions. Over the interval [2, 6], the average rate of change of v is the
1 answer:
You might be interested in
Answer:
a) The cut off value of the highest 50% is 6.16%.
b) The cut off value of the highest 16% is 8.8%.
c) The cut off value of the lowest 2.5% is 0.7%.
d) The cut off values of the middle 68% is 3.4% for the lower bound and 8.8% for the higher bound.
Step-by-step explanation:
The 68–95–99.7 rule is an empirical rule to remember the percentage of values that lie within a band around the mean in a normal distribution with a width of two, four and six standard deviations respectively.
a) Cut off value of the highest 50%
It corresponds to the half that has the higher returns, which are the ones that are above the mean (0 standard deviation). The cut off value in this case is the mean x=6.16%.
b) Cut off value of the highest 16%
In this case, we use the 68 rule-value, which means that 68% of the values lies within a band around the mean with a width of two standard deviations.
The percentage that lies out of this band is 100%-68%=32%, of which 16% lies above the band (the highest 16%) and 16% lies below the band.
We can estimate, according to this rule, that the highest 16% are above the cutoff value X of μ+1σ:
The cut off value of the highest 16% is 8.8%.
c) Cut off of the lowest 2.5%
In this case, we use the 95 rule.
The lowest 2.5% lies below two standards deviation less of the mean
The cut off value of the lowest 2.5% is 0.7%.
d) Cut off of the middle 68%
In this case we calculate the band within one standard deviation.
The cut off values of the middle 68% is 3.4% for the lower bound and 8.8% for the higher bound.
Answer:
The balance is
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above