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suter [353]
3 years ago
5

Sam measured the height of a window frame as 5.23 feet, but the actual height was 6 feet. What is the percentage of error in Sam

's measurement?
Mathematics
2 answers:
jonny [76]3 years ago
7 0

Answer: 12.83%

Step-by-step explanation:

Given : Sam measured the height of a window frame as 5.23 feet, but the actual height was 6 feet.

i.e. Estimated height = 5.23 feet

Actual height = 6 feet

Then, the percentage of error in Sam's measurement will be :-

\%\text{Error}=\dfrac{|\text{Estimated height-Actual height}|}{\text{Actual height}}\times100\\\\=\dfrac{|5.23-6|}{6}\times100\\\\ =\dfrac{0.77}{6}\times100\\\\=12.8333333333\approx12.83\%

Hence, the percentage of error in Sam's measurement= 12.83%

gavmur [86]3 years ago
6 0

Answer:

12.83%

Step-by-step explanation:

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