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givi [52]
2 years ago
6

Question 6 (5 points)

Mathematics
1 answer:
AnnyKZ [126]2 years ago
4 0

The amplitude of the function is 3/2 after comparing with the general equation option (C) is correct.

<h3>What is cos function?</h3>

It is defined as the function which is in the form of cosine waves in nature, and it has a domain of all real numbers and lies between the [a, a] where is a amplitude of the function.

We have a cos function:

y = 3/2 cos(3x) + 1

We know,

f(x) = acos(bx - c) + d

The above function represents the cos function where:

a = amplitude

b = is the period of the function

c = phase shift

d = vertical shift

On comparing we get:

a = 3/2

Thus, the amplitude of the function is 3/2 after comparing with the general equation option (C) is correct.

Learn more about the cos function here:

brainly.com/question/14397255

#SPJ1

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A tourist attraction experienced a 3.75% fall in visitor numbers in June, compared to the previous month due to bad weather Ther
Romashka-Z-Leto [24]

Answer:

(A) 126400

(B) 8.57%

Step-by-step explanation:

(A) According to the scenario, calculation of the given data are as follows,

Visitors in June = 121660

Let visitors in May = X

Difference in visitors number in June = 3.75% decrease

So, we can calculate the visitors number in may by using following formula,

Number of visitors in June = X - 3.75%X

121660 = 96.25%X

X = (121660 × 100) ÷ 96.25

X = 126400

Hence, Number of visitors in may = 126400

(B). Difference in visitors in July than in May = 4.5% increase

So, Number of visitors in July = 126400 + (126400 × 4.5%)

= 126400 + 5688

= 132088

Now, we will calculate increase in percentage by using following formula,

Increase percentage = (132088 - 121660)  ÷ 121660

= 10428 ÷ 121660

= 0.0857 or 8.57%

7 0
3 years ago
What value is equivalent to 13 − 2(1 − 15) ÷ 4?
Bas_tet [7]
Use bodmas.
13-2(-14)/4
-11(-14)/4
154/4
46
7 0
3 years ago
Read 2 more answers
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
What two products do you get when you cross-multiply the fractions 2/5 and 3/8?
jarptica [38.1K]
Answer: a. 10 and 12

explanation:
4 0
4 years ago
The sum of eighty five and five times a number is equal to twenty. Find the number
pochemuha
(20 - 85) / 5 = -13 is the answer
3 0
4 years ago
Read 2 more answers
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