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fredd [130]
2 years ago
12

40 points please Please help me

Mathematics
1 answer:
Lunna [17]2 years ago
6 0

Answer:

19.51 units = x

Step-by-step explanation:

Here is one way :

Height = 18 cos 47 = 12.276

then     cos 51 = 12.276 /  x

                 x = 12.276 / cos 51 = 19.51

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Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan
inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}

                         = \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \  \ \\\\

                                                                                                       k= 2,3..........10For option B:

P(X=k | X \geq 2 ) =  \sum^{10}_{i=2}  \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}

                                                                                                k= 2,3, 4.........10

8 0
3 years ago
In the figure the diagonals of a rhombus ABCD intersect at O . If <ADC = 120°, OC = 3cm and OD = 4cm , find
Sunny_sXe [5.5K]

Answer:

did you get it?

7 0
3 years ago
Please help I gotta pass this test
Paraphin [41]

Answer:

h=128

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
(ANSWER FOR FREE BRAINPOINTS!) (FIRST TO ANSWER GETS BAINLIEST) The local park has a rectangular swimming pool that measures 40
iren [92.7K]

Answer:

9 yards

Step-by-step explanation:

Since both pools are similar, therefore the ratio of their length and width would be equal. That is:

Length of the current swimming pool : length of the new swimming pool = width of the current swimming pool : width of the new swimming pool

Thus, we can set up a proportion as shown below:

Let the width of the new swimming pool be x.

40 : 24 = 15 : x

\frac{40}{24} = \frac{15}{x}

Cross multiply

40*x = 15*24

40x = 360

Divide both sides by 40

x = \frac{360}{40}

x = 9

The width of the new swimming that is smaller would be 9 yards.

4 0
2 years ago
How to multiply double digits
liq [111]
27 * 35 
= 20*35 + 7 * 35
= 700 + 245
= 945
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3 years ago
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