(ax + b)/c ≤ b
ax+b ≤ cb
ax ≤ cb - b
x ≤ (cb-b)/a
<span>the correct equation is
- 4j² + 3j - 28 =0
ax² + bx + c,
a = -4, b=3 c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
The answer there is no real roots</span>
Answer:
Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .
*angles in a quadrilateral is 360 degree
*2x+3x+5x+8x=360
*18x=360
*x=360/18
*x=20
now substitute x in these:
2x=2x20=40
3x=3x20=60
5x=5x20=100
8x=8x20= 160
so these are the following angles: 40,60,100 and 160
* r^2