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2 years ago

Expand . ( 3x –2 ) 2 please help me with this.

Mathematics

2 answers:

BartSMP [9]2 years ago

4 0

Answer:

6x-4

Step-by-step explanation:

3x•2= 6x

-2•2=-4

Ainat [17]2 years ago

3 0

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Answer: $\textsf{9x}^2\textsf{ - 12x + 4}$

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Given: $\textsf{(3x - 2)}^2$

Find: $\textsf{Simplify the expression}$

Solution: It looks like 2 is at the end of the parenthesis where the power would be instead of distributing the number. If so the following steps would be followed.

Expand

$\textsf{(3x - 2)}^2$

$\textsf{(3x - 2)(3x - 2)}$

$\textsf{(3x * 3x) + (3x * (-2)) + (3x * (-2)) + (-2 * (-2))}$

Simplify

$\textsf{9x}^2\textsf{ - 6x - 6x + 4}$

$\textsf{9x}^2\textsf{ - 12x + 4}$

Therefore, after following the provided information we are able to determine that the expanded form would be 9x^2 - 12x + 4.

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago

How much does a 5 lb 11 oz roast weigh in grams?

Maurinko [17]

Answer:

2268 grams or 2 kg 268 g

Step-by-step explanation:

How to convert Pounds to Grams

1 pound (lb) is equal to 453.59237 grams (g).

1 lb = 453.59237 g

The mass m in grams (g) is equal to the mass m in pounds (lb) times 453.59237:

m(g) = m(lb) × 453.59237

In this case,

Convert 5 lb to grams:

2267.96 approximately convert to nearest thousands.

m(g) = 5 lb × 453.59237 = 2268 g or 2 kg 268 g

5 0

3 years ago

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MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

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3 years ago

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podryga [215]

The answer is d. A small business loan

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3 years ago

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Aleksandr [31]

Answer:

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3 years ago