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Verdich [7]
3 years ago
12

The Frosty Ice-Cream Shop sells sundaes for $2 and banana splits for $3. On a hot summer day, the shop sold 8 more sundaes than

banana splits and made $156.
How do you solve this problem?
Mathematics
1 answer:
svlad2 [7]3 years ago
4 0

The shop sold 36 sundaes and 28 banana spilts

<em><u>Solution:</u></em>

Let "a" be the number of sundaes sold

Let "b" be the number of banana spilts sold

Cost of 1 sundaes = $ 2

Cost of 1 banana spilt = $ 3

<em><u>On a hot summer day, the shop sold 8 more sundaes than banana splits and made $156</u></em>

Therefore,

Number of sundaes sold = 8 + number of banana spilts sold

a = 8 + b ------- eqn 1

<em><u>Also, given that they made $ 156</u></em>

<em><u>Therefore, we frame a equation as</u></em>:

Number of sundaes sold x Cost of 1 sundaes + number of banana spilts sold x Cost of 1 banana spilt = 156

a \times 2+b \times 3 = 156

2a + 3b = 156 ---------- eqn 2

<em><u>Substitute eqn 1 into eqn 2</u></em>

2(8 + b) + 3b = 156

16 + 2b + 3b = 156

16 + 5b = 156

5b = 156 - 16

5b = 140

<h3>b = 28</h3>

<em><u>Substitute b = 28 in eqn 1</u></em>

a = 8 + 28

<h3>a = 36</h3>

Thus the shop sold 36 sundaes and 28 banana spilts

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