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Hatshy [7]
2 years ago
10

What is the correlation coefficient r for the data set? enter your answer to the nearest hundredth in the box. r = x y 25 240 26

242 27 230 28 229 28 220 28 219 29 200 30 202 31 184 32 180
SAT
1 answer:
TEA [102]2 years ago
4 0

The use of the excel tool given in the image above will give you the correlation coefficient of r for the data set is as r=-0.96

<h3>What is the correlation coefficient  about?</h3>

Note that  one have to find first,  the mean of all of your the x-values, and then one can find the mean of all of the y-values.

Note that  one can use the excel to find the mean which will be 28.4 and 214.6 for both.

The next step is to find the standard deviation for x and y. Then, you have to put it into the formula that is given for the correlation coefficient."

When you use the excel, R will be  -0.9647 and when you round up to the nearest hundredth,  the answer will be -0.96.

Learn more about Excel from

brainly.com/question/25879801

#SPJ1

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inna [77]
2 will agree and 2 will disagree so the answer is 4
7 0
3 years ago
refer to the accompanying data set of mean​ drive-through service times at dinner in seconds at two fast food restaurants. const
CaHeK987 [17]

Step-by-step explanation:

Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.

The standard error is SE = s/√n = 62.6/√50 = 8.85.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

180.56 ± 1.960 × 8.85

180.56 ± 17.35

(163, 198)

Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.

The standard error is SE = s/√n = 49.2/√50 = 6.96.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

152.96 ± 1.960 × 6.96

152.96 ± 13.64

(139, 167)

4 0
2 years ago
B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len
Citrus2011 [14]

Answer:

The additional words is 2^n

Explanation:

Given

B(n) = 2^n

Required

Determine the additional words; i.e. B(n + 1) - B(n)

From the given parameters, we have that;

B is a function of n

Such that;

B(n) = 2^n

To calculate B(n+1), we simply substitute n + 1 for n

B(n) = 2^n

B(n + 1) = 2^{n + 1}

Applying laws of indices

B(n + 1) = 2^{n} * 2^1

B(n + 1) = 2^{n} * 2

B(n + 1) = 2(2^{n})

Calculating Additional Binary Code;

B(n + 1) - B(n)

Substitute values for B(n + 1) and B(n)

B(n + 1) - B(n) = 2(2^n) - 2^n

Express 2^n as 2^ n * 1

B(n + 1) - B(n) = 2(2^n) - 2^n * 1

Express 1 as 2^0

B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0

Factorize

B(n + 1) - B(n) = 2^n(2 - 2^0)

B(n + 1) - B(n) = 2^n(2 - 1)

B(n + 1) - B(n) = 2^n(1)

B(n + 1) - B(n) = 2^n

Hence, the additional words is 2^n

8 0
3 years ago
A student is bouncing on a trampoline. At her highest point, her feet are 95 cm above the trampoline. When she lands, the trampo
rosijanka [135]

The time she spent in contact with the trampoline is 0.1619 seconds.

The objective of this question is to determine for how long she is in contact with the trampoline?

The conservational force is exerted on the trampoline is equivalent to the sum of the potential energy at the highest point and the elastic energy at the lowest point.

∴

From the given information;

\mathbf{mg \dfrac{(95 +25)}{100} = \dfrac{1}{2}k ( \dfrac{25}{100})^2}

\mathbf{m\times g\times 1.2 = k(0.03125)}

\mathbf{m\times 9.8 \times 1.2 = k(0.03125)}

\mathbf{\dfrac{m}{k} = \dfrac{(0.03125)}{9.8 \times 1.2}}

\mathbf{\dfrac{m}{k} = 0.002657}

Using the Simple Harmonic Motion to determine the time at which she is in contact with the trampoline, we have;

\mathbf{t= \dfrac{T}{2}}

\mathbf{t= \dfrac{2 \pi}{2} \sqrt{\dfrac{m}{k}}}

where;

  • \mathbf{\dfrac{m}{k} = 0.002657}

\mathbf{t= \dfrac{2 \pi}{2} \times \sqrt{0.002657}}}

\mathbf{t=0.1619\ sec}}

Learn more about the time period of a Simple Harmonic Motion here:

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What are similarities between banks and credit unions?
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They both offer checking and savings accounts, mortgages, loans on homes and autos. These things are the things that they have in common.
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