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1 year ago

Can someone do this for me please?! Just the answer pls

Mathematics

1 answer:

stiv31 [10]1 year ago

3 0

Answer:

see the attachment photo!

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Measure of angle A = 5 X, measure of angle B = 2X, measure of angle C = 110 degrees

Alex17521 [72]

5x+2x+110=180
7x=70
x=10

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2 years ago

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During which one-day interval did she work the most hours?

Karo-lina-s [1.5K]

Um well lets see there is no question so the day that ends in y

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3 years ago

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On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th

Schach [20]

Answer:

Average speed is 37.35 mi/h

Step-by-step explanation:

given data

leave = 34 minutes before

church distance = 12.0 miles

average speed first 17 minutes = 5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × $\frac{17}{60}$

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

remaining distance Average speed = $\frac{distance}{time}$

Average speed = $\frac{10.584}{\frac{17}{60}}$

Average speed is 37.35 mi/h

3 0

2 years ago

Find area of parallelogram multiple choice

alina1380 [7]

In ∆ABD

$\\ \sf\longmapsto Area=\dfrac{1}{2}bh=\dfrac{1}{2}(7\times 4)$

In ∆BCD

$\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)$

Now

IN PARALLELOGRAM ABCD

$\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)+\dfrac{1}{2}(7\times 4)$

Option A

4 0

2 years ago

What is the area of a section of pavement that is 10 ft wide and 70 yd long? Give your answer in square feet. I think I have th

Elenna [48]

Answer:

2100 ft²

Step-by-step explanation:

1 yard is 3 ft, so 70 yards is (70 yd)×(3 ft/yd) = 210 feet.

The area of the pavement is the product of its length and width:

area = (210 ft)(10 ft) = 2100 ft²

_____

If you keep the units with the numbers as I have done here, you find that the product of (10 ft) and (70 yd) does not have the units of ft². Rather, the units are ft·yd, which is <em>not what the problem is asking for</em>.

6 0

2 years ago