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3 years ago

How much green ooze was carried all??

Mathematics

2 answers:

WITCHER [35]3 years ago

7 0

Answer:

$5$ cups.

Step-by-step explanation:

We have been given a line plot, which represents the cups of green ooze. We are asked to find the total number of cups.

To find the total number of cups, we will add all the given quantities as shown below:

$2\times\frac{1}{4}+2\times\frac{3}{8}+2\times\frac{1}{2}+3\times\frac{5}{8}+\frac{7}{8}$

$\frac{2\times1}{4}+\frac{2\times3}{8}+\frac{2\times1}{2}+\frac{3\times5}{8}+\frac{7}{8}$

$\frac{2}{4}+\frac{6}{8}+\frac{2}{2}+\frac{15}{8}+\frac{7}{8}$

Make a common denominator:

$\frac{2\times2}{4\times2}+\frac{6}{8}+\frac{2\times 4}{2\times 4}+\frac{15}{8}+\frac{7}{8}$

$\frac{4}{8}+\frac{6}{8}+\frac{8}{8}+\frac{15}{8}+\frac{7}{8}$

Add numerators:

$\frac{4+6+8+15+7}{8}$

$\frac{40}{8}$

$5$

Therefore, there are $5$ cups of green ooze in all.

LUCKY_DIMON [66]3 years ago

6 0

There is 4 1/2 cups of green ooze

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Answer:

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Step-by-step explanation:

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3 years ago

Find the volume of the figure.<br> A 1,053 M^3<br> B 2,106 M^3<br> C 513 M^3<br> D 58,5 M^3

vampirchik [111]

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3 years ago

The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers

Airida [17]

Answer:

a) $P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)$

$P(Z>2.357)=1-P(Z$

b) $P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)$

$P(Z$

$P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}$

$P(-1.179$ Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where $\mu=3$ and $\sigma=\sqrt{9}=3$

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we want to find this probability:

$P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})$

And using a calculator, excel or the normal standard table we have that:

$P(Z>2.357)=1-P(Z$

Part b

$P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}})$

And using a calculator, excel or the normal standard table we have that:

$P(Z$

Part c

For this case we want this probability:

$P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}$

And using a calculator, excel or the normal standard table we have that:

$P(-1.179$

7 0

3 years ago

The ratio of the number of tomato plants in Inessa’s garden to the number of tomato plants in Ralph’s garden was 5:6. After 1 2

Dennis_Churaev [7]

Inessa = X

Ralph = Y

By the given ratio X/Y = 5/6

Solve for X: X = 5/6 * Y

Now Inessa gives 1/2 of hers to Ralph, which then totals 850"

Y + 1/2X = 850

Replace x :

Y + 1/2 * 5/6 * Y = 850

SImplify:

Y + 5/12Y = 850

Multiply both sides by 12 to remove the fraction:

12Y + 5Y = 10200

Simplify:

17Y = 10200

Divide both sides by 17:

y = 10200 / 17

y = 600

Ralph originally had 600 plants.

4 0

3 years ago

11) A 12-sided dic is rolled. What is the probability of getting a multiple of 3 or a number less than 3?

dmitriy555 [2]

Answer:

6/12

1/2

Step-by-step explanation:

First, we need to find how many multiples of three there are, and how many numbers less than three there are on a 12 sided die.

Multiples of 3: 3, 6, 9 ,12

Less than 3: 2, 1

When calculating the probability of rolling a number, the actual number is arbitrary- instead, you need to know how many of numbers exist to fit the requirements. In this case, it's 6 total. Since there's 12 possibilities on a 12 sided die, the probability would be 6 out of 12. You could also simplify the fraction, but both are equivalent.

I hope this helps!

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3 years ago