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2 years ago

A Circular pie with a diameter of 10” Is cut into six equal pieces. What is the surface area of two slices of pie?

Mathematics

1 answer:

-Dominant- [34]2 years ago

4 0

To solve this question, let's find the surface area of the entire pie and then divide it by 6 for each slice.

The area of a circle is pi*r^2. We are given the diameter, so divide that by 2 to get the radius.

Now that you have the area, divide by 6. That is the area of each slice. The problem asks for the area of 2 slices though, so multiply that by 2.

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What other customary units of capacity have the same relationship as pints and quarts

Stella [2.4K]

Gallons, Fluid Oz, Cups

5 0

3 years ago

Read 2 more answers

Cassie rolls a fair number cube with 6 faces labeled 1 through 6. She rolls the number cube 300 times.Which result is most likel

Leona [35]

There would be no most likely result because every time that she rolls that dice there is a 1/6 chance of getting any given number.

7 0

4 years ago

@jdoe As promised. The link will be whatever.

Lady_Fox [76]

Ok, so we see in
y=a(x-h)^2+k
vertex is (h,k)
vertex is highest or lowest point
on one side, it goes up and other side it goes down

if a is positive, then it goes down then up
if a is negative, it goes up then down

we see
f(x)=2(x+3)^2+2
2 is positive
goes down then up
vertex is (-3,2)

so decreases from -infinity to -3 or ininterval
(-infinity,-3)

answer is first option

6 0

3 years ago

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago

Solve for x: -3x + 3 < 6 x>-1 x<-1 x<-3 x>-3

Triss [41]

Answer:

D is the correct answer

Step-by-step explanation:

first you subtract the 3 from the left side and add it to the right side. then you divide both side by negative 3 and flip the less than sign to a greater than sign

5 0

3 years ago