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Svetach [21]
3 years ago
8

Which system is equivalent to StartLayout Enlarged left-brace 1st row y = 9 x squared 2nd row x + y = 5 EndLayout StartLayout En

larged left-brace 1st row 5 minus x = 9 x squared 2nd row y = 5 minus x EndLayout StartLayout Enlarged left-brace 1st row y = 9 y squared minus 90 y + 225 2nd row x = y minus 5 EndLayout StartLayout Enlarged left-brace 1st row 5 + x = 9 x squared 2nd row y = 5 + x EndLayout StartLayout Enlarged left-brace 1st row y = 3 x 2nd row x + 3 x = 5 EndLayout
Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

The answer is C.) (2,5)

Step-by-step explanation:

I Have Edge

Stella [2.4K]3 years ago
4 0

Answer:

3rd option

Step-by-step explanation:

trust me

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The sum of 3 integers is 194. the sum of the first and second integers exceeds the third by 80. The third integer is 45 less tha
kirill115 [55]
Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45

Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239

Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102

Solving for y,
y = -2(102) + 239
y = 35

Solving for z,
z = 102 - 45
z = 57
5 0
3 years ago
Please help me I will give brain and I will be so happy btw 20 points
iVinArrow [24]

Answer:

The first answer and the second answer.

5 0
3 years ago
Read 2 more answers
If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y
algol [13]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

5 0
3 years ago
Help fast
yarga [219]

Answer:

The first one

Step-by-step explanation:

5 0
2 years ago
A map is made of a park. The scale from the park to the map is 36 mi to 6 cm. The length of Great Oaks Trail is 4.5 cm on this m
Ilya [14]

Answer:

Salamander Trail is longer than Great Oak Trail

Step-by-step explanation:

The given parameters are;

The scale of the map is 36 mi = 6 cm

The length of Great Oak Trail = 4.5 cm

The scale of a different map is 24 mi = 3 cm

The length of Salamander Trail = 3.5 cm

Therefore, we have;

The actual length of Great Oak Trail based on the first map is given as follows;

36 mi = 6 cm

6 cm = 36 mi

1 cm = 36 mi/6 = 6 mi

4.5 cm = 4.5 × 6 mi = 27 mi

The actual length of Salamander Trail based on the second  map is given as follows;

24 mi = 3 cm

3 cm = 24 mi

1 cm = 24 mi/3 = 8 mi

3.5 cm = 3.5 × 8 mi = 28 mi

Therefore, Salamander Trail with an actual length of 28 mi is longer than Great Oak Trail which has an actual length of 27 mi.

7 0
3 years ago
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