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2 years ago

Tomás bought a new car for $41,000. If the value of the car depreciates by 17% each year, determine the value

1 answer:

6 0

This is a means of reducing the cost of a goods or an asset over time. The value of the car after 9 years is approximately $888

<h3>Depreciation</h3>

This is a means of reducing the cost of a goods or an asset over time.

Mathematically, the cost of goods after a particular year is expressed as:

P(t) = P0e^-rt

Given

P0 = $41000
rate r = 17% = 0.17
time t = 9 years

Substitute

P(17) = 41000r^0.17(9)
P(17) = 4100(0.21653)

P(17) = 887.79

Hence the value of the car after 9 years is approximately $888

Learn more on depreciation here: brainly.com/question/1287985

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WUCLUJ

mash [69]

Answer:

81 degrees

Step-by-step explanation:

A quadrilateral has four interior angles which sum up to 360 degrees.

As we are given that two angles are right angles which means the sum of two angles will be 180 degrees and the third angle is 99 degrees.

As we know that the four angles sum up to 360 degrees.

Let A,B,C and D denote the four angles,

Then

Sum of angles = 360

A+B+C+D=360

90+90+99+D=360

279+D=360

D=360-279

D= 81 degrees

So the fourth angle is 81 degrees ..

7 0

4 years ago

The french club is selling coupon books for $8.25 each. How many coupon books must be sold to earn $5,940?

leonid [27]

720 because 5940 divided by 8.25 is 720

4 0

4 years ago

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Use the method of "undetermined coefficients" to find a particular solution of the differential equation. (The solution found ma

Naddika [18.5K]

Answer:

The particular solution of the differential equation

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$ + $\frac{1}{37}185e^{6x})$

Step-by-step explanation:

Given differential equation y''(x) − 10y'(x) + 61y(x) = −3796 cos(5x) + 185e6x

The differential operator form $(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

<u>Rules for finding particular integral in some special cases:-</u>

let f(D)y = $e^{ax}$ then

the particular integral $\frac{1}{f(D)} (e^{ax} ) = \frac{1}{f(a)} (e^{ax} ) if f(a)$ ≠ 0

let f(D)y = cos (ax ) then

the particular integral $\frac{1}{f(D)} (cosax ) = \frac{1}{f(D^2)} (cosax ) =\frac{cosax}{f(-a^2)}$ f(-a^2) ≠ 0

Given problem

$(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

P<u>articular integral</u>:-

$P.I = \frac{1}{f(D)}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + \frac{1}{D^2-10D+61}185e^{6x})$

P.I = $I_{1} +I_{2}$

we will apply above two conditions, we get

$I_{1}$ =

$\frac{1}{D^2-10D+61}( −3796 cos(5x) = \frac{1}{(-25)-10D+61}( −3796 cos(5x) ( since D^2 = - 5^2)$ $= \frac{1}{(36-10D}( −3796 cos(5x) \\= \frac{1}{(36-10D}X\frac{36+10D}{36+10D} ( −3796 cos(5x)$

on simplification we get

= $\frac{1}{(36^2-(10D)^2}36+10D( −3796 cos(5x)$

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{1296-100(-25)}$

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$

$I_{2}$ =

$\frac{1}{D^2-10D+61}185e^{6x}) = \frac{1}{6^2-10(6)+61}185e^{6x})$

$\frac{1}{37}185e^{6x})$

Now particular solution

P.I = $I_{1} +I_{2}$

P.I = $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$ + $\frac{1}{37}185e^{6x})$

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3 years ago

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not clear way ..... clear it

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Traveling at 65 miles/hour how many feet can you travel in 22 minutes

tangare [24]

Here is what another branily user said:

If you are travelling at 65 mph, you have to think of it as if you are moving at a constant speed. By dividing 65 by 60, you are calculating how many miles you are moving each minute. In doing so, you can calculate that you are moving at 1.083333 miles each minute. That's approximately 5720 feet per minute. (This is calculated by multiplying 1.083333 by 5280 (the number of feet in a mile)). 5720 x 22 minutes, you will have traveled 125,840 feet.

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3 years ago

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