Answer:
2nd option
Step-by-step explanation:
Consider the coordinates of T(- 3, 3 ) → T' (3, - 1 )
- 3 → 3 is 6 units right in the positive x-direction
3 → - 1 is 4 units down in the negative y- direction
Then translation rule is
(x, y ) → (x + 6, y - 4 )
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
The apothem represents one side of the right triangle to be solved. Specifically, it represents the height of the triangle.
The radius of the polygon represents the hypotenuse of the right triangle that is going to be solved.
Therefore, we can infer that the radius of the polygon is greater than the apothem because the hypotenuse is greater than all sides of a triangle.
Answer:
the radius of the polygon is greater
Answer:
Step-by-step explanation:
Notice that we are requested to perform a horizontal shift of on unit to the right. Recall that a horizontal shift of one unit to the right involves the operation of subtracting from the variable "x" one unit.
Therefore, this implies the following mathematical transformation to the variable "x":
where we simply completed distributive property to get rid of the parenthesis inside the absolute value.
Your answer would be B and C, hope this helps! :D
