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miskamm [114]
2 years ago
12

Find the area of a circle whose radius is 2.5cm

Mathematics
2 answers:
Marizza181 [45]2 years ago
6 0

Answer:

19.6349540849

Step-by-step explanation:

π × 2.5^2 = 19.6349540849

Marina CMI [18]2 years ago
4 0
2.5 squared is 6.25
pi multiplied by 6.25 is 19.6
The area of a circle whose radius is 19.6cm
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stiv31 [10]
Answer: 3 hours and 25 min
3 0
3 years ago
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ILL GIVE YOU BRAINLIEST IF ANSWERED RIGHT!!!! If the quadratic equation has the form y = ax ^2and y = ax ^2+ c, then their axis
Sliva [168]

Answer:

x = 0

Step-by-step explanation:

The axis of the symmetry has the same x coordinate of the vertex

V (x) = -b/2a

in both equations b is equal to 0 and a 0/a number different from 0 gives always 0 as a result

7 0
3 years ago
I need help asap plz I will mark branlist
Nesterboy [21]
1) Mean= Sum of total Observation/ Total no.of observation
Mean= 42/6=7
option (b) 7


2)To calculate Median first arrange the numbers in a numerically ascending order.

Since, there are even no.of total Observation median will be the mean of two middlemost terms.

3,6,7,9,9,10

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7 0
3 years ago
An investment project involves an immediate outlay of $8 million. The net cash flows received at the end of years 1, 2, and 3 wi
My name is Ann [436]

Answer:

(c) 0.46 million

Step-by-step explanation:

As provided immediate cash outlay = $8 million.

This will represent cash outflow at period 0, as it is made immediately, no time period has lapsed.

Cash inflows as provided and the respective present value factor are:

Year         Cash Inflow       Factor              Discounted Value

1                 $3 million         0.9091                $2,727,300

2                $4 million         0.8264               $3,305,600

3                 $2 million         0.7513                $1,502,600

Total present value of cash inflow = $7,535,500

Therefore, net present value = $7,535,500 - $8,000,000 = - $464,500

That is - 0.46 million

Correct option is

(c) 0.46 million

4 0
3 years ago
A and B are centres of two circles of radii 8 cm and 1 cm such that AB =13 cm and angle ACB =90 degree where C is the centre of
Artyom0805 [142]

Answer:

50.28 sq. cm.

Step-by-step explanation:

A and B are centers of two circles of radii 8 cm and 1 cm such that AB =13 cm.

Now, angle ACB =90 degree where C is the center of another circle which touches the above two circles.

Now, ABC forms a right triangle where AB = 13 cm, AC = (r + 8) cm and BC = (1 + r) cm.

{Where r is the radius of the circle C.

Applying Pythagoras Theorem. AB² = AC² + BC²

⇒ 13² = (r + 8)² + (r + 1)²

⇒ 169 = r² + 16r + 64 + f² + 2r + 1

⇒ 2r² + 18r - 104 = 0

⇒ r² + 9r - 52 = 0

⇒ (r + 13)(r - 4) = 0

Hence, r = 4 {As the value of r can not be negative}

Therefore, the area of the circle C is π(4)² = 50.28 sq. cm. (Answer)

7 0
3 years ago
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