All categories

2 years ago

Find the area of a circle whose radius is 2.5cm

Mathematics

2 answers:

Marizza181 [45]2 years ago

6 0

Answer:

19.6349540849

Step-by-step explanation:

π × 2.5^2 = 19.6349540849

Marina CMI [18]2 years ago

4 0

2.5 squared is 6.25
pi multiplied by 6.25 is 19.6
The area of a circle whose radius is 19.6cm

You might be interested in

Need answer for this.

cestrela7 [59]

$\\ \sf\longmapsto cosV=\dfrac{Base}{Hypotenuse}$

$\\ \sf\longmapsto cosV=\dfrac{UV}{VT}$

Put the values

$\\ \sf\longmapsto cosV=\dfrac{28}{53}$

$\\ \sf\longmapsto cosV=0.528$

4 0

3 years ago

Read 2 more answers

Divide. Reduce the answer to the lowest terms.<br><br> 3/8 ÷ 1/7

Kamila [148]

Answer:

21/8

Step-by-step explanation:

3/8 x 7/1 = 21/8

3 0

3 years ago

Read 2 more answers

PLEASE HELP!! I NEED HELP WITH ALGEBRA!!

Lunna [17]

I don’t know at ALL!!!

3 0

4 years ago

The diagram of a lawn is shown below. If one bag of grass seed covers 3,000 square feet, how many bags of grass seed are needed

zepelin [54]

Answer:

4 and half (4.5) bags of grass seed are needed to cover the lawn

Step-by-step explanation:

7 0

2 years ago

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0

3 years ago