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beks73 [17]
2 years ago
8

8-2 (i+1) < 12 − 7i + 4i true.

Mathematics
1 answer:
IrinaK [193]2 years ago
3 0

Answer:

True

Step-by-step explanation:

8-2 (i+1) < 12 − 7i + 4i

<u>Left side of the inequality:</u>

8 - 2(i + 1)        <em>distribute</em>

8 - 2i - 2        <em>simplify</em>

(8 - 2) - 2i

6 - 2i

<u>Right side of the inequality:</u>

12 − 7i + 4i        <em>simplify</em>

12 − 3i

<u>Combine: </u>

6 - 2i < 12 − 3i

6 is less than 12

3i is less than 2i

leads to the assumption that the statement is true

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exis [7]

Answer:

Mean: 7.1, median: 7, mode: 4

Step-by-step explanation:

The mean, also known as the average, is equal to the sum of all the numbers divided by how many numbers there are.

4 + 8 + 11 + 6 + 4 + 5 + 9 + 10 + 10 + 4 = 71

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3 years ago
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{ \leadsto{ \sf{ \green{ {x}^{4}  + 25 = 26 {x}^{2} }}}} \\  \\ { \leadsto{ \sf{ \green{ {x}^{4}  - 26 {x}^{2}  + 25 = 0}}}} \\  \\ { \sf{ \underline{ \blue{let  \:  \: {x}^{2} \:  be \: equal \: to \: a}}}}

{ \leadsto { \green{ \sf{ {a}^{2}  - 26a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - (a + 25a) + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - a - 25a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{a(a - 1) - 25(a - 1) = 0}}}}

{ \leadsto{ \sf{ \green{(a - 1)(a - 25) = 0}}}} \\  \\ { \sf{ substituting \: value \: of \: a}} \\  \\ { \rightarrow{ \sf{ \blue{( {x}^{2}  - 1)( {x}^{2}  - 25) = 0}}}} \\  \\ { \sf {{x}^{2}  = 1}}  \\ { \sf{ \underline{x = \: ±  \: 1}}} \\  \\  \\ { \sf {x}^{2}  = 25}  \\ { \sf{ \underline{x =  \: ± \: 5}}}

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