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sineoko [7]
3 years ago
8

(x+6)(x+3) = x²+6x+3x+18 What’s the proof here ?

Mathematics
1 answer:
avanturin [10]3 years ago
8 0
All real numbers

distribute (x+6)(x+3) to get x^2+6x+3x+18

your equation now looks like this:

x^2+6x+3x+18= x^2+6x+3x+18

because the equations are equal, the answer is all real numbers
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DRaw the graph of f (x) = 1/2 x² -2x where -2 &lt; x &lt; 4​
Flura [38]

Answer:

Graphs Attached Below

Step-by-step explanation:

Hello!

Standard form of a quadratic: ax^2 + bx + c= 0

From our Equation:

  • a = 1/2
  • b = -2
  • c = 0

There are several values that are needed to drawing a parabola:

  • y - intercept
  • Axis of Symmetry (AOS)
  • Vertex
  • x - intercepts

<h2>Y-intercept</h2>

Standard form of a quadratic: ax^2 + bx + c= 0

The y-intercept is the "c" value. Given that our equation has a "c" value of 0, the y -intercept is 0.

<h2>Axis of Symmetry</h2>

A parabola is always symmetrical vertically. The line in which the fold happens is the Axis of Symmetry.

To calculate the AOS, we use the formula AOS = \frac{-b}{2a}, from the values of the equation.

Calculate

  • AOS = \frac{-b}{2a}
  • AOS = \frac{-(-2)}{2(0.5)}
  • AOS = \frac{2}{1}
  • AOS = 2

The Axis of Symmetry is a vertical line, so the AOS is the line x = 2.

<h2>Vertex</h2>

The vertex is the highest or lowest point on the graph of a parabola. It resides on the AOS of the graph.

To calculate the vertex, we simply have to find the y-value, given that we have the x-value from the AOS. We can find the y-value by plugging in the AOS for x in the original equation.

Calculate

  • f(x) = \frac12x^2 - 2x
  • f(x) = \frac12 (2)^2 - 2(2)
  • f(x) = 2 - 4
  • f(x) = -2

The y-value is -2. The vertex is (2, -2).

<h2>X-intercepts</h2>

The x-intercepts are the points where the graph intersects the x-axis (y = 0).

Solve by Factoring

  • f(x) = \frac12 x^2 - 2x
  • 0 = \frac12x(x - 4)
  • x = 0, x = 4

The roots are (0,0) and (4,0).

<h2>Graph</h2>

Now we just draw the y-intercept, vertex, AOS, and the x-intercepts, and draw a curved line between them.

<em>Image Attached</em>

<h2>Domain Restrictions</h2>

The Domain (x-values) are being restricted to all x-values that are greater than or equal to -2 and less than 4.

That means we remove the parts of the line that don't belong in that domain.

<em>Image Attached</em>

3 0
2 years ago
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