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Y = - 10x has a negative slope, m = -10, and a y-intercept of (0, 0).
The graph includes the following points:
{(-2, 20), (-1, 10), (0, 0), (1, -10), (2, -20)}.
Attached is a screenshot of the graph, where it includes the y-intercept crossing along the point of origin, (0, 0).
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The graph includes the following points:
{(-2, 20), (-1, 10), (0, 0), (1, -10), (2, -20)}.
Attached is a screenshot of the graph, where it includes the y-intercept crossing along the point of origin, (0, 0).
Please mark my answers as the Brainliest, if you find this helpful :)
Answer:
M'(0,-6),N'(2,0),P'(5,0) and Q'(7,-6)
Step-by-step explanation:
We are given that the vertices of quadrilateral MNPQ are M(-3,-2),N(-1,4),P(2,4) and Q(4,-2).
We have to translate the quadrilateral MNPQ using vector <3,-4>
The translate the coordinates of vertices (x,y) using the vector <a,b> is given by the rule
Using the rule
The new coordinates of M
The new coordinates of N
The new coordinates of P
The new coordinates of Q
Hence, after translation the new vertices of quadrilateral are
M'(0,-6),N'(2,0),P'(5,0) and Q'(7,-6)