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tankabanditka [31]
3 years ago
6

1. Determine whether the regular hexagon has reflection symmetry, rotation symmetry, both, or neither. If it has reflection symm

etry, state the number of axes of symmetry and draw all the symmetry lines. If it has rotation symmetry, state the angle of rotation. For each type of symmetry, explain how you can tell the figure does or does not have the given symmetry.

Mathematics
1 answer:
lana [24]3 years ago
3 0
The regular hexagon has both reflection symmetry and rotation symmetry.

Reflection symmetry is present when a figure has one or more lines of symmetry. A regular hexagon has 6 lines of symmetry. It has a 6-fold rotation axis.

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Rotation symmetry is present when a figure can be rotated (less than 360°) and still look the same as before it was rotated. The center of rotation is a point a figure is rotated around such that the rotation symmetry holds. A regular hexagon can be rotated 6 times at an angle of 60°

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AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

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The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

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we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

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-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

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