Answer: B, $4.41 per shirt
Step-by-step explanation:
To figure this out you want to first take the 200 shirts and multiply them by the cost of $2.80. This gives you a total of $560, without tax. The tax is 5%, so you want to take 560 and multiply it by .05 to find the amount of tax. This leaves you with $28 of taxes. Add that onto the already cost of $560, and it gives you a grand total of $588. She wants to sell the shirts with a 150% markup, so all you do is first find what Michelle really paid for each shirt with tax. Take the total cost of 588 and divide it by the number of total shirts which is 200. 588/200=$2.94 per shirt that Michelle paid. Times that by 1.5% and you get $4.41 per shirt that Michelle is selling.
The functions that the left endpoint lead to an under approximation and right endpoints lead to and over approximation is the positive and increasing function.
<h3>How to illustrate the function?</h3>
It should be noted that function simply means the illustration that shows the relationship between the variables.
In this case, the functions that the left endpoint lead to an under approximation and right endpoints lead to and over approximation is the positive and increasing function.
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Am not quite sure but it’s 17
Hope this helped
F(x) = 1/(x+2) & g(x) = x/(x-3)
(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:
1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)
Answer: f(x) = –(x + 1)^2 – 2 and f(x) = –|2x| + 3
Step-by-step explanation:
The maximum value of the function
g(x) = -(x + 3)^2 - 4
we can derivate the function and find the root:
g' = -2x = 0
then x = 0 give us the maximum value of g(x)
g(0) = -9 - 4 = -11
a) f(x) = –(x + 1)^2 – 2
The maximum value of this function is also at x = 0 (because the construction is the same as before) then the maximum is:
f(0) = -1 - 2 = 3
This maximum is bigger than the one of g(x)
b) f(x) = –|x + 4| – 5
We have a minus previous to a modulus, so the maximum value will be when whe have the minimum module of x, that is for x = 0, here we have that the maximum is;
f(x) = - I4I - 5 = -9
Is the same maximum of g(x)
c) f(x) = –|2x| + 3
Same as before, the maximum is at x = 0
f(0) = 0 + 3 = 3
The maximum is bigger than the one of g(x)
