Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime => ![2^1](https://tex.z-dn.net/?f=2%5E1)
Prime Factorization of 4 is:
2 x 2 => ![2^2](https://tex.z-dn.net/?f=2%5E2)
Prime Factorization of 7 is:
7 is prime => ![7^1](https://tex.z-dn.net/?f=7%5E1)
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28
Answer:
8, -2
Step-by-step explanation:
Answer:
15%, Pennies
Step-by-step explanation:
This should have the least amount of being chosen considering there are fewer pennies than there are any other coin. Hope this helped!
-Kirito
Your answer would be 1.16 !!