Answer:
Step-by-step explanation:
Negative 2/3 means -2/3
Hence;
1 + (-2/3) - (-m)
= 1 - 2/3 + m (positive x negative = negative, negative x negative = positive)
Substituting 9/2 for the value of m
= 1 - 2/3 + 9/2
The L.C.M = 6
= ( 6 - 4 + 27)/6
= 29/6
2x + 6y = 14y - 19x^2 + 12 is a non-linear equation
Step-by-step explanation:
Lets define a linear equation first.
A linear equation is an equation in which there is no variable with exponent greater than 1 or the degree of the equation is 1.
So,
<u>x + 12 = -8x + 10 - 2y</u>
The equation is a linear equation because the degree of the equation is 1.
<u>x = 8x + 19 - 10y</u>
The equation is a linear equation because the degree of the equation is 1.
<u>2x + 6y = 14y - 19x^2 + 12</u>
The equation involve a term with exponent 2 which makes the degree of the equation 2 making it a quadratic equation
<u>2x + 13y + 14x - 7 = 16y - 3</u>
The equation is a linear equation because the degree of the equation is 1.
Hence,
2x + 6y = 14y - 19x^2 + 12 is a non-linear equation
Keywords: Linear, quadratic
Learn more about equations at:
#LearnwithBrainly
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
-3r + 15 ---> answer
Step-by-step explanation:
r < 5
You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.
3r < 15
Now, subtract 15 from both sides, you will get this:
3r < 15
-15 -15
-------------
3r — 15 < 0
Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.
So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l
Answer:
Step-by-step explanation:
4x+2y<3
y<-2x + 
