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e-lub [12.9K]
2 years ago
9

Someone, please help! I really don't understand congruent triangles

Mathematics
1 answer:
WARRIOR [948]2 years ago
5 0

Answer:

  D.  (CPCTC)

Step-by-step explanation:

Your proof that the triangles are congruent is complete at the 4th step. In Step 5, you are asked to draw a conclusion about corresponding angles in those congruent triangles.

__

<h3>what is congruence?</h3>

Two geometric objects are congruent if they are identical in size and shape by any measure. If they are not labeled, you cannot tell them apart. Every measure of one is identical to the corresponding measure of the other. The location and orientation of congruent figures does not affect their congruence. You can move them, rotate them, flip them over, and they remain congruent.

This property, "corresponding parts of congruent triangles are congruent," is abbreviated "CPCTC." Once you have demonstrated objects are congruent, you can use this fact to relate measures of the objects that may not have been part of the demonstration.

<h3>proving congruence</h3>

<u>general</u>

We generally work with plane geometric figures that are polygons or have well-defined curved edges. Polygon figures are comprised of straight sides of fixed length. At each vertex, where sides meet, an angle is formed. Corresponding sides form corresponding angles.

The sides are generally named by the vertices at either end. The angles may be named by the vertex where it is located, or by the names of the sides that make it up.

In triangle ABC, for example, the vertices have labels A, B, and C. The sides are AB, AC, and BC. And the angles are A, B, and C, or BAC, ABC, ACB. (The vertex of the angle is the middle letter.)

To prove polygons are congruent, you must show corresponding angles are congruent, and corresponding sides are congruent. Generally, the number of sides will put constraints on the size of the angles. (A 6-sided polygon will have 6 angles that total 720°, for example.)

<u>triangles</u>

When the polygon is a triangle, the constraints on side lengths and angles generally mean there are shortcuts to proving congruence. The postulates that tell you what these are have been given mnemonic abbreviations. When we say, "angle" or "side" in this context, we are referring to congruent corresponding angles in the two triangles, or congruent corresponding sides.

  • AAS -- two consecutive angles and a side adjacent to one of them will prove congruence
  • ASA -- two angles and the side between them will prove congruence
  • SAS -- two sides and the angle between them will prove congruence
  • SSS -- three sides will prove congruence

These can also be applied to right triangles, where one angle is known to be 90°. In addition, there is a theorem that only applies to right triangles:

  • HL -- the hypotenuse and one leg will prove congruence. (Note that the hypotenuse is opposite the known 90° angle, so this is effectively an SSA congruence statement, only applicable to right triangles.)

<u>your proof</u>

The triangles in your figure have a side marked with a single hash mark. This means those corresponding sides in the two triangles are congruent to each other.

There is an angle marked with two (2) arcs in each triangle. This marking means those corresponding angles are congruent. Likewise for the angles marked with three (3) arcs. You will notice the 3-arc angle, 2-arc angle, and 1-hash mark side are in the same order in the two triangles. This means the AAS congruence postulate applies, as is claimed on line 4 of your proof.

<h3>using congruence</h3>

As you have seen, we only need to show <em>some</em> parts of a triangle are congruent in order to show <em>all</em> parts of the triangle are congruent. When we make a claim about corresponding parts that weren't an explicit part of the proof, we are essentially relying on the definition of congruent polygons. For triangles, that definition is summarized by the abbreviation CPCTC.

Line 5 of your 2-column proof is making a claim about corresponding angles of the triangle. That claim is supported by CPCTC.

_____

<em>Additional comment</em>

Choices A and C refer to congruence postulates, as discussed above. Those have no relation to the claim regarding angles ACB and XZY.

The "corresponding angles theorem" tells you corresponding angles are congruent where a transversal crosses parallel lines. It has no relation to the angles in this problem.

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I got this question wrong, so if someone can please help me with this, I would really appreciate it! Please and thank you!
jeyben [28]

Answer:

15 in.

Step-by-step explanation:

The area of the left-most square is 81 in.^2. Area = L*W (Length times width), and since we know squares are always equal on each side, we can do 9*9=81. That means the left side of the triangle is 9.

Then, we move to the bottom-most square. The perimeter is 48 in. As said before, we know all sides of a square must be equal. We will divide 48 by 4, as that's how many sides a square has (mind-blowing!), and we get 12. That means, using the Pythagorean Theorem, (9^2) + (12^12) = C^2. We can simplify this to 81 + 144 = C^2, or 225 = C^2 if you add those two numbers together. We can take the square root of both sides to get C = 15!

3 0
3 years ago
Read 2 more answers
Find sin(α) and cos(β), tan(α) and cot(β), and sec(α) and csc(β). The hypotenuse is 7 and side is 4.
Shalnov [3]

The triangle is missing, so i have attached it.

Answer:

1)sin(α) = 4/7

2)cos(β) = 4/7

3)tan(α) = 4/√33

4)cot(β) = 4/√33

5)sec(α) = 7/√33

6)csc(β) = 7/√33

Step-by-step explanation:

(1) sin(α)

From trigonometric ratios, we know that sine of an angle in a right angle triangle = opposite/hypotenuse.

Now, in this question, the opposite side to α is 4 and the hypotenuse is 7. Thus, sin(α) = 4/7

2) cos(β)

Cosine of an angle = adjacent side/hypotenuse.

In the question, the adjacent side to the angle β is 4 and the hypotenuse is 7. Thus, cos(β) = 4/7

3)tan(α)

tan of an angle = opposite/adjacent side. The opposite side to α is 4, but the adjacent side is unknown.

Using the pythagoras theorem,

Adjacent side = √(7² - 4²)

Adjacent side = √(49 - 16)

Adjacent side = √33.

Thus, tan(α) = 4/√33

4) cot(β)

cot of an angle is the reciprocal of tangent of same angle.

The adjacent side to β is 4 while the opposite is √33.

So, tan(β) = (√33)/4

cot(β) = 1/tan(β)

cot(β) = 1/[(√33)/4]

cot(β) = 4/√33

5)sec(α)

sec of an angle is equal to one divided by cosine of that same angle, so it equals hypotenuse divided by the adjacent. The hypotenuse is 7 and the adjacent side to α is √33.

Thus, sec(α) = 1/cosα = 7/√33.

6) csc(β)

Csc of an angle is equal to one divided by sine of same angle, so it equals hypotenuses divided by the opposite. The hypotenuse is 7 and the opposite side to β is √33.

Thus, csc(β) = 1/sin(β) = 7/√33

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3 years ago
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Ksivusya [100]

Answer:

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Step-by-step explanation:

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Find the quotient of -7/5÷-9/5​
neonofarm [45]

Answer:

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Step-by-step explanation:

-7/5÷-9/5

- cancelled with each other

(7×5)/(9×5)

5 also cancelled with 5

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