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lakkis [162]
3 years ago
15

Multiply (6x-6)(x+6)

Mathematics
2 answers:
Damm [24]3 years ago
4 0

Hey there!

(6x + (-6)) (x +6)  \\ \\  6x(x) + 6x(6) + (-6) (x) + -6 (6)  \\ \\ 6x(x) = 6x^2 \\ \\ 6x(6) = 36x \\ \\ -6(6) = -36 \\ \\ 6x^2 + 36x - 6x -36 \\ \\  36x - 6x = 30x \\ \\ Answer: 6x^2 + 30x -36

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

Blizzard [7]3 years ago
3 0

FOIL method : F = First , O = Outer , I = Inner, L = Last

(6x-6)(x+6)

First: 6x * x = 6x^2

Outer: 6x * 6 = 36x

Inner: -6 * x = -6x

Last: -6 *6 = -36

Put these in order and we get : 6x^2 + 36x -6x -36

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6 0
3 years ago
The price of a Thanksgiving turkey sold at Fry's is equal to the original cost in dollars that Fry's paid
Irina-Kira [14]

Answer: The largest per pound at which turkeys sold

Step-by-step explanation:

hope this helps!

7 0
3 years ago
Read 2 more answers
Find the value of x in the triangle shown below 3 6<br><br> 5<br><br> √18<br><br> √27<br><br> 4
Cerrena [4.2K]

a^2 + b^2 = c^2

In this case we're looking for C

so

(3)^2 +  b^2 = (6)^2

9 + b^2 = 36

b^2 = 36-9

√b^2 = √27

b = 3√3

4 0
3 years ago
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Factor the polynomial function over the complex numbers?? <br><br><br><br> F(x)= x^4 -x^3-2x-4
pav-90 [236]

Answer: The factor form of the function F(x) is (x+1)(x-2)(x^2+2), where  (x^2+2) gives two complex roots.

Explanation:

The given function is,

F(x)=x^4-x^3-2x-4

According to the rational root theorem 1 and -1 are the possible roots of each polynomial.

Put x=-1

F(-1)=(-1)^4-(-1)^3-2(-1)-4=0

Since the value of F(x) is 0 at x=-1 therefore the -1 is a root of given polynomial and (x+1) is a factor of F(x).

Use synthetic division method to divide the polynomial by (x+1).

The last row of the synthetic division shows the coefficient of remaining polynomial.

F(x)=x^4-x^3-2x-4=(x+1)(x^3-2x^2+2x-4)

At x=2 the value of F(x) is 0, therefore (x-2) is a factor of F(x).

Use synthetic division method to divide the polynomial by (x-2).

F(x)=(x+1)(x-2)(x^2+2)

Therefore the roots of F(x) are,

-1,2,\pm i\sqrt{2}

F(x)=(x+1)(x-2)(x+i\sqrt{2})(x-i \sqrt{2} )

Where (x+1)(x-2) factors with real root and (x+i\sqrt{2})(x-i \sqrt{2} ) are factors with complex roots.

8 0
3 years ago
Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.
Nesterboy [21]
Add the common difference to a term to get the next term.
-10
-10 + (-2) = -12
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etc.

The sequence is
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28
3 0
3 years ago
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