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ira [324]
2 years ago
15

Please Expand the following: 3q(r – 2q)

Mathematics
2 answers:
11Alexandr11 [23.1K]2 years ago
4 0

Answer:

3qr - 6q²

Step-by-step explanation:

3q(r - 2q) ← multiply each term inside the parenthesis by 3q

= 3qr - 6q²

Yuki888 [10]2 years ago
3 0

Answer:

3qr – 6q²

Step-by-step explanation:

3q(r – 2q)

<u>E X P A N D I N G :-</u>

3qr – 6q²

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Wich equation representa the line shown on the graph?
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the correct answer is the third one

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True or false<br> The solution set of 2x+5=x-3is {-8}
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True

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2x+5=x-3 is (-8)

This is the correct answer

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When debby's 3ds is fully charged it last for 8 hours. if she only charged it 3/5 full how long did it last her?
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What is 14.876 - 4.96
d1i1m1o1n [39]

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4 years ago
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Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?
Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so


\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}


so we're really looking for a line whose slope is 3 and runs through (1,5)


\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2

4 0
3 years ago
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