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kirill115 [55]
2 years ago
7

Calculate the area of the trapezoid. Use paper to show your work. The figure is not drawn to scale.

Mathematics
1 answer:
lutik1710 [3]2 years ago
8 0

The area of a trapezium with the given dimensions is: 198 cm²

<h3>What is the Area of a Trapezium?</h3>

Area of a trapezium = 1/2(a + b)h, where h is the heght of the trapezium and a and b are the length of its bases.

Given the following:

  • a = 12 cm
  • b = 21 cm
  • h = 12 cm

Area of a trapezium = 1/2(12 + 21)12

Area of a trapezium = 198 cm²

Learn more about the area of trapezium on:

brainly.com/question/1463152

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268.08

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katrin [286]

Answer:

  • (-3, 5), (4, 1), (-1, -5)

Step-by-step explanation:

270° counterclockwise rotation is same as 90° clockwise

<u>The rule is:</u>

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<u>Given points:</u>

  • A(-5, -3), B(-1, 4), C(5, -1)

<u>Translated points:</u>

  • A' = (-3, 5)
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3 years ago
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VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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B = 22, mZZ = 30°; Find a.
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There is no a to find in your problem

Step-by-step explanation:

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