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Dahasolnce [82]
2 years ago
13

How?

Mathematics
1 answer:
Contact [7]2 years ago
3 0

Step-by-step explanation:

You can wait some time like 3 days but as a rule of thumb, there has to be 2 people to give 1 of them brainliest

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adult tickets to space city amusement park cost x dollars. childrens tickets cost y dollars.the henson family bought 3 adult and
ASHA 777 [7]
See the pic-the top two equations are your "system" of equations to solve

8 0
4 years ago
I got number 7 wrong can someone help me with the answer and the work
Amiraneli [1.4K]
To figure out this problem break it down into steps.

We know that there are 1 - 25 or 25 cards in total, one card is taken out and not replaced so now there are only 24 cards.

25 - 1 = 24.

Find the probability of getting one number greater than 10, this would be all numbers from 10 - 25, which are 25 - 10 = 15 options to choose that will give you a value greater than 10.

Probability = 15/24 = 5/8.

For 2 cards simply multiply the probability by itself to get 2 cards where the number is greater than 10.

5/8 • 5/8 = 25/64.

The probability of getting 2 cards that are greater than 10, are 25/64.

This is the solution.







4 0
3 years ago
In a certain​ city, it was recorded that 17 and one third inches of rain fell over a​ 24-hour period. How much rain fell per hou
agasfer [191]
(17 1/3) / 24 = x/1
cross multiply
24x = 52/3
x = 52/3 * 1/24
x = 52/72 = 13/18 inches per hr
4 0
3 years ago
BRAINLIEST!!!!
vaieri [72.5K]

Answer:   has a maximum

              the maximum is  11

Step-by-step explanation:

f(x)= -5x^2-10x+6

the function f(x)= ax^2+bx+c=0  has a<0  so the equation has a maximum

I know V has the coordonate x=-b/2a,  and y=-(b^2-4ac)/4a

b^2-4*a*c= (-10)^2-4*(-5)*6=100+120=220

so -b/2a=-(-10)/-2*5=+10/-10=-1 and

    -(b^2-4ac)/4a=-220/4*(-5)=-220/-20=22/2=11

so  V( -1, 11)

and  the maximum is  11

   

4 0
3 years ago
10-3-6x-A simplified​
nordsb [41]
10 - 3 - 6x - A


Answer: 7 - 6x - A


This is the simplest the original expression can get :)

4 0
3 years ago
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