To solve for a variable, you need to get it (x) by itself.
2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula
a = 2 , b = -4 , c = -1
x =

Plug in your values
x =

Simplify
x =

Simplify
x =

Simplify by removing a 2 from every term
x =

Simplify by taking the fraction apart
x =

Change

to 1
x = 1

Simplify

to
x = 1
Assuming those are the legs of the triangle and that you need to find the hypotenuse... I would use the formula: a^2+b^2=c^2
It doesn't matter what a and b are, just fill it in.
25^2+35^2=c^2
625+1225=c^2
1850=c^2
Take the square root of 1850, it isn't a perfect square so I got: 43.01.
If you want, just round it to 43, idc.
So, if I were to check my work, I would need to remember that the hypotenuse is the longest side.
Since 43 is the hypotenuse, it is the longest side.
Convert 2/5 to a decimal and you get .4, or 40%. 40% of the band members also sing, so yes, the band has the same number of string instrument players and singers.
The second equation is <span>-5-2y=2, then
</span>
<span>-2y=2-(-5),
</span>
-2y=2+5,
-2y=7,
y=7÷(-2),
y=-3.5.
The first equation is 2x+5y=16, subtitude y=-3.5 in this equation, then
2x+5·(-3.5)=16,
2x-17.5=16,
2x=16-(-17.5),
2x=16+17.5,
2x=33.5,
x=33.5÷2,
x=16.75.
Answer: (16.75,-3.5)