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asambeis [7]
3 years ago
11

Balance the equation by inserting coefficients as needed. equation: C 2 H 6 O+O 2 longrightarrow CO 2 +H 2 O

Chemistry
1 answer:
shepuryov [24]3 years ago
4 0

The coefficients needed to balance the equation would be 2, 7, 4, and 6 respectively.

<h3>Balancing chemical equation</h3>

This requires that the number of atoms of each element is the same both on the reactant and product's sides.

Hence, the balanced equation of the reaction becomes:

2C_2 H_6 O+ 7O_2 --- > 4CO_2 +6H_2 O

Thus, the coefficient for each species would be 2, 7, 4, and 6 respectively.

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

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Explanation:

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Calculate the mass percent of ba(no3)2 in this solution, assuming the density of the solution is 1.000 kg/l.
viktelen [127]
You forgot to include the known characteristics of the solution.

I searched them and copy here:

volume: 1.000 liter

M = 0.0190 M

Now, you can start with the definition of mass percent.

mass percent = (grams of solute / grams of solution) * 100

grams of solute are obtained from the molar concentration:

M = (number of moles of solute) / (volume of solution in liters)

where number of moles = (grams) / (molar mass)

=> M = (grams of solute / molar mass of solute) / (volume of solution in liters)

=> grams of solute = M * (volume of solution in liters) * (molar mass of solute)

And density = (kg of solution / volume of solution in liters) =>

kg of solution = density * volume of solution in liters

grams of solution = density * (volume of solution in liters) * 1000 g/kg

=> mass percent = M * (volume of solution in liters) * (molar mass) / (density * volume of solution in liters * 1000 g/ kg) * 100

=> mass percent = M * molar mass * 10 / density

now replace the values known:

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molar mass of Ba(NO3)2 = 137.327 g/mol + 2*14.007 g/mol + 2*3*15.999 g/mol = 256.335 g/mol

=> mass percent = 0.0190 mol/liter * 256.335 g/mol * 10  kg/ g / (1.000 kg/liter)

=> mass percent = 48.7%
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