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Allisa [31]
2 years ago
7

Which is the graph of the function f(x) = x³ + x² + x + 1?

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
8 0
Theres no graphs but this is how the function looks like

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How is taking away sandbags different from adding
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Your limting the amount of sandbags you have if you take away and when your adding your adding more sandbags.
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3 years ago
Calvin is mixing colored gravel for the bottom of his fish tank. He mixes 12 pounds of blue gravel with 3 pounds of purple grave
Flura [38]

Answer:

B.4

Step-by-step explanation:

I did 12 divided by 3 = 4

8 0
3 years ago
Which number is a factor of 14, but not a multiple of 2?
bonufazy [111]
7 is a factor of 14 and is not a multiple of 2.
5 0
3 years ago
Use the order of operations to find the value of the expression. 2 + 3 × 16 − 2 × 21 − 3
kolezko [41]

Answer:

5

Step-by-step explanation:

=2+(3)(16)-(2)(21)-3

=2+48-(2)(21)-3

=50-(2)(21)-3

=50-42-3

=8-3

=5

Hope this helped! :)

6 0
2 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
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