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dezoksy [38]
3 years ago
15

The ordered pair D (-4,-2) has been plotted for you. If you reflected coordinate d over the x-axis, which point from part A woul

d be resulting coordinate? A= (-4,2) b= (2,4) c=(4,-2)

Mathematics
1 answer:
Serjik [45]3 years ago
6 0
A= (-4,2)

The x value (-4) stays the same when reflected over the x-axis, so only the y-value gets reflected and therefore changed.
The resultant coordinate is (-4,2)
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Step-by-step explanation:

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Solve the inequality 3x - 5
SSSSS [86.1K]
The anwser would be -15  
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Please help, performance task: trigonometric identities
AnnZ [28]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<h3>How to solve the trigonometric equations?</h3>

<u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Read more about trigonometry equations at:

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2 years ago
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4 0
3 years ago
Simplify (5x2 + x – 11) – (3x² + 4x – 17)
tatiyna

Answer:

2 x^2 - 3 x + 6

Step-by-step explanation:

Simplify the following:

-(3 x^2 + 4 x - 17) + 5 x^2 + x - 11

-(3 x^2 + 4 x - 17) = -3 x^2 - 4 x + 17:

-3 x^2 - 4 x + 17 + 5 x^2 + x - 11

Grouping like terms, 5 x^2 - 3 x^2 + x - 4 x - 11 + 17 = (5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17):

(5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17)

5 x^2 - 3 x^2 = 2 x^2:

2 x^2 + (x - 4 x) + (-11 + 17)

x - 4 x = -3 x:

2 x^2 + -3 x + (-11 + 17)

17 - 11 = 6:

Answer: 2 x^2 - 3 x + 6

3 0
3 years ago
Read 2 more answers
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