-4.625,-5.2,-4 4/5, -4 8/11 order least to greatest
1 answer:
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Question:
The temperatures at several times of the day are shown in the coordinate plane below. The x-axis represents the number of hours before or afternoon. For example, -1 would represent 11 a.m. The y-axis represents the temperature in degrees Celsius.At 5 p.m, the temperature is halfway between the temperature at 2 p.m. and the temperature at 8 p.m.
What coordinates represent the temperature at 5 p.m.?
Answer:
(5, 2)
=> At 5pm, the temperature is at 2⁰C
Step-by-step Explanation:
Coordinates of any point on a cartesian/coordinate plane is represented by (x, y). Where x is the number at the point on z-axis, while y is the number at the same point on the y-axis.
From the diagram of the coordinate plane attached below, we can simply find out what coordinates represent the temperature at 5pm.
==> Given that the temperature at 5pm is half way between the temperature at 2pm (y=7) and temperature at 8pm (y=-3), the point that is being referred to = [7+(-3)] ÷ 2 = ⁴/2 = 2 (i.e. 2 on the y axis representing temperature)
*The position of the point is indicated in the second picture that is attached below.
At that position of the point, we have 2 as the coordinate for the y axis representing temperature, and at that same position, we have 5 on the x-axis representing the number of hours.
Therefore, coordinates of the point (x, y) representing 5p.m = (5, 2)
==> At 5pm, the temperature is at 2⁰C
<u>Given</u>:
Given that the side length of the base of the square pyramid is 16 inches.
The height of the pyramid is 22.1 inches.
We need to determine the volume of the square pyramid.
<u>Volume of the square pyramid:</u>
The volume of the square pyramid can be determined using the formula,
where B is the area of the base and h is the height of the pyramid.
Substituting B = (16 × 16) and h = 22.1, we get;
Thus, the volume of the pyramid is 1885.9 cubic inches.
9514 1404 393
Answer:
see below
Step-by-step explanation:
Reflection across the x-axis just changes the signs of the y-coordinates. Rotation -120° about B' is difficult to do by hand. The transformation rule for that is ...
(x, y) ⇒ (x·cos(-120°) +y·sin(-120°), -x·sin(-120°) +y·cos(-120°))
(x, y) ⇒ ((-(x-3) +(y+2)√3)/2 +3, (-(x-3)√3 -(y+2))/2 -2)
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It looks like your problem is presented in GeoGebra, which makes reflection and rotation easy.
