Question

Oh gosh I dunno any of this- Trigonometry

Answer 1

Answer:

Step-by-step explanation:

Triangle 1:

Problem:

Find leg $a$ of a right triangle if hypotenuse $c=10$ and angle $\alpha =25^o$.

Solution:

$a$ ≈ $4.2262$

Explanation:

To find leg $a$ use formula:

                                     $\text{sin}(\alpha )=\frac{a}{c}$

After substituting $\alpha =25^o$ and $c=10$ we have:

                                           $sin(25^o)=\frac{a}{10}\\0.4226=\frac{a}{10}\\a=0.4226\times10$

                                           $a=4.2262$

Triangle 2:

Problem:

Find leg $b$ of a right triangle if leg $a=4$ and angle $\alpha =20^o$.

Solution:

$b$ ≈ $10.9899$

Explanation:

To find leg $b$ use formula:

                                        $\text{tan}(\alpha)=\frac{a}{b}$

After substituting $\alpha =20^o$ and $a=4$ we have:

                                                    $tan(20^o)=\frac{4}{b}\\0.364=\frac{4}{b}\\b=\frac{4}{0.364}\\b =10.9899$

Answer 2

You need to use SOHCAHTOA.
Sin (opposite/hypotenuse)
Cos (adjacent/hypotenuse)
Tan (opposite/adjacent)

For the first photo, you would use
Tan( opposite/adjacent)
4/x = tan(20)
Then you just change the equation to have x on the side by itself.
(4)(tan20) = x
Then write that into the calculator.

For the second problem, you use
Sin(opposite/hypotenuse)
Sin(25)=x/10
Change the equation to have x by itself.
Sin(25)(10)=x
Then plug it into the calculator.