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2 years ago

9

Solve using substitution x-y= 6 4x+2y=36

1 answer:

Elza [17]2 years ago

5 0

X=6+y
4(6+y) +2y=36
24+6y=36
6y=12
Y=2
X=8

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Please... I... need... HELP

Alja [10]

Here!
(x+4)+(x+2)+(x+5)= (x+1)+(x+1)+(x+3)+(x+3)
First you want to write the whole equation out. Make each perimeter equal to each other.
Then add both sides separately.
(x+4)+(x+2)+(x+5)
=3x+11

and

(x+1)+(x+1)+(x+3)+(x+3)
=4x+8

Now that you've simplified each side, solve like a normal equation.
3x+11 = 4x+8
-3x -3x
11 = x+8
-8 -8
3=x

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3 years ago

What is 6.9 to the nearest 10th

Dvinal [7]

The number 6.9 is already rounded to the nearest tenth.

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3 years ago

Which is a solution to the equation y=5x-6

Vilka [71]

$y=5x-6 \\ \\ the \ graph\ of \ a \ linear \ equation \ is \ a \ straight \ line$

4 0

3 years ago

Read 2 more answers

Find h(g(n)) when h(n) = 2n + 5<br> and g(n) = n +4

Evgen [1.6K]

Answer:

2n+13

Step-by-step explanation:

$h(g(n))\\h(n)=2n+5\\g(n)=n+4\\h(n+4)=2(n+4)+5\\=2n+8+5\\=2n+13$

5 0

3 years ago

Mia found the area of a polygon The area is 32 square cm.

solniwko [45]

Answer:

Only the isosceles trapezoid has an area of 32 cm².

Step-by-step explanation:

Let's calculate the area of each polygon.

For the two triangles we have:

$A_{t} = \frac{bh}{2} = \frac{2 cm*4 cm}{2} = 4 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle we have:

$A_{r} = bh = 6 cm*4 cm = 24 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle trapezoid we have:

$A_{rt} = A_{t} + A_{r} = (4 + 24) cm^{2} = 28 cm^{2}$

So, this polygon does not have an area of 32 cm².

Finally, for the isosceles trapezoid:

$A_{it} = A_{t}*2 + A_{r} = (4*2 + 24) cm^{2} = 32 cm^{2}$

This polygon does have an area of 32 cm².

Therefore, only the isosceles trapezoid has an area of 32 cm².

I hope it helps you!

8 0

3 years ago