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klemol [59]
2 years ago
14

Evaluate 4(x+5)(x+1) (x+3)(x-3) for x = 5.

Mathematics
2 answers:
Ainat [17]2 years ago
5 0

Answer:

3840

Step-by-step explanation:

Given expression:

4(x+5)(x+1)(x+3)(x - 3)

To:

Evaluate the expression ; for x = 5.

Solution:

  • 4(x+5)(x+1)(x+3)(x - 3)

Evaluate x = 5 :

  • 4(5+5)(5+1)(5+3)(5 - 3)

Simplify using PEMDAS rule:

P : Parentheses

E : Exponents

M : Multiplication

D : Division

A : Addition

S : Subtraction

  • (4)(10)(5+1)(5+3)(5−3)
  • 40(5+1)(5+3)(5−3)
  • (40)(6)(5+3)(5−3)
  • (240(5+3)(5−3)
  • (240)(8)(5−3)
  • 1920(5−3)
  • (1920)(2)
  • 3840

Hence, after evaluating the given expression for x = 5 , the answer'll be 3840.

telo118 [61]2 years ago
3 0

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to evaluate

\large\pmb{4(x+5)(x+1)(x+3)(x-3)} for x=5.

\triangle~\fbox{\bf{KEY:}}

  • Use <u>PEMDAS</u>. With the help of this acronym, we will not make any mistakes in the Order of Operations!

<u />

Here's what <u>PEMDAS</u> stands for:

<u>P=P</u>arentheses

<u>E=E</u>xponents

<u>M=M</u>ultiplication

<u>D=D</u>ivision

<u>A=A</u>ddition

<u>S=S</u>ubtraction

So, let's start computing...

///\\\///\\\///\\\///\\\///\\\////\\\///\\\///\\\///\\\///\\//\\\///\\\///\\\///\\\\///\\\\///\\\///\\\///\

                                   <u>Evaluating the expression</u>

First, substitute 5 for x:

\star~\large\pmb{4(5+5)(5+1)(5+3)(5-3)}

Now, use the Order of Operations.

The first operation here is:

\dag <u>P=Parentheses</u>

<u></u>

So we need to perform the operations inside the parentheses first:

\star~\large\pmb{4(10)(6)(8)(2)}

The next operation is <u>multiplication</u><u>, </u>since we don't have any exponents here:

\star~\large\pmb{40\times6\times8\times2}

Multiply!

\star~\Large\pmb{3840}~~\square\!\!\!\!\!\checkmark

That's the value of the expression 4(x+5)(x+1)(x+3)(x-3) for x=5.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

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