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love history [14]
3 years ago
9

What is the equation of the perpendicular bisector of the segment joining points A(1, 1) and B(5, 7)?

Mathematics
1 answer:
Elden [556K]3 years ago
8 0
Bisector must pass through the mid-point, so we have to find out that mid-point of the segment:

mid point = x₁+x₂ / 2 , y₁+y₂/2
= 1 + 5 / 2 , 1 + 7 / 2
= 6/2 , 8/2
= (3, 4)

Slope of given segment = m = y₂-y₁ / x₂- x₁
m = 7-1 / 5-1
m = 6/4
m = 3/2

Now, segment which is perpendicular, will have the opposite & reciprocal slope, So, it would be: -2/3

We know, y - y₁ = m(x - x₁)
y - 4 = -2/3(x - 3)
y - 4 = -2/3x + 2
y = -2/3x + 6

In short, Your Final Answer would be: y = -2/3x + 6

Hope this helps!
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7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

  x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

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