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2 years ago

Someone please help with this !!!!!

Mathematics

2 answers:

lianna [129]2 years ago

8 0

Answer:

$5^{\circ}$

Step-by-step explanation:

$~~~~~~~\tan \theta = \cot 85^{\circ}\\\\\implies \tan \theta = \tan\left(90^{\circ} - 85^{\circ} \right)\\\\\implies \tan \theta = \tan 5^{\circ}\\\\\implies \theta = 5^{\circ}$

dolphi86 [110]2 years ago

6 0

Answer:

[[[[[[[[[[[[[[[[

Step-by-step explanation:

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The endpoint is the ___ of the angle

Phoenix [80]

Hey there!

ANSWER: <u>vertex</u>

<h2>EXPLANATION:</h2>

Fill in the blank:

The endpoint is the <u>vertex</u> of the angle.

This is your answer because an angle is formed by two rays which are the sides of an angle and they have an endpoint called the vertex.

Hope this helps!

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3 years ago

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Andrej [43]

3.1 is like a example when it is hiding a zero behind it and you find this when you do a math problem and you don't put zero in front of a number like 100-89 you don't write "011" so that is why it is like that

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3 years ago

How many terms are in the expression <br> 5x^3-8x^2y+4xy-4

bazaltina [42]

Answer:

<h2>4 terms</h2>

Step-by-step explanation:

Term 1: 5x^3

Term 2: 8x^2y

Term 3: 4xy

Term 4: 4

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3 years ago

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Lunna [17]

Answer:

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Step-by-step explanation:

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3 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago