y2-y1/x2-x1
8-(-1)/3-4=
9/-1=
-9
the slope of the line is -9
Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,


t = 1.875 seconds
Put the values of t in equation (1). So,

h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
You would set up the problem like this: 3n-25=38
To solve for n:
3n-25=38
+25 +25 (Add 25 to both sides)
3n=63
/3 /3 (Divide by 3 on both sides)
n=21
The answer is 21.
The volume is 508.94 cm^3