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Vladimir79 [104]
3 years ago
10

Let f(x) = x - 3 and g(x) = x + 11 find f(x) times g(x) What is the answer?

Mathematics
1 answer:
notsponge [240]3 years ago
6 0

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

Sorry if its wrong :(

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A construction crew has repaired 1.37 miles of a highway. The total length of the highway to be repaired is 7.9. How many miles
JulijaS [17]

Answer:

Part A: m+1.37=7.9

Part B: 6.53 miles are left to be repaired.

Step-by-step explanation:

Given,

Length of repaired part = 1.37 miles

Total length to be repaired = 7.9 miles

Miles left to be repaired = m

Part A:

Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.

Miles left to be repaired + Length of repaired part = Total length to be repaired

m+1.37=7.9

Part B

How many miles are left to be repaired?

Subtracting 1.37 from both sides

6.53 miles are left to be repaired.

Keywords: length, subtraction

Step-by-step explanation:

6 0
3 years ago
Solve the equation.<br> 2x – 3 + 4x = 21<br> x=-12<br> x= -6<br> x = 4<br> x = 6
WARRIOR [948]

Answer:

x = 4

Step-by-step explanation:

2x-3+4x=21

Isolate the variable by dividing each side by the factors that don't contain the variable

3 0
3 years ago
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Show that (2+3) + 6= (6+3) +2
lara [203]

Answer: use order of operstions

Step-by-step explanation:

4 0
3 years ago
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Make g the subject of this relation​
zhannawk [14.2K]

Answer:

see explanation

Step-by-step explanation:

Simplify the radical

\frac{U}{\frac{1}{f}+\frac{1}{g}  }

= \frac{U}{\frac{g+f}{fg} }

= \frac{Ufg}{g+f}

Square both sides

T² = \frac{Ufg}{g+f} ( multiply both sides by (g + f) )

T²(g + f) = Ufg ( distribute left side )

T²g + T²f = Ufg ← subtract Ufg from both sides

T²g - Ufg + T²f = 0 ← subtract T²f from both sides

T²g - Ufg = - T²f ← factor out g from each term on the left side

g(T² - Uf) = - T²f ← divide both sides by (T² - Uf)

g = - \frac{T^2f}{T^2-Uf} = \frac{T^2f}{Uf-T^2}

6 0
3 years ago
In which quadrant is (4,-5) located
Vinvika [58]
4 in (4,-5) implies positive x-axis.
-5 in (4,-5) implies negative y-axis.

Since x is positive and y is negative in fourth quadrant, so the answer is

QUADRANT IV (or 4th quadrant.
3 0
3 years ago
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