<u>Answer:</u>
- The first four terms are <u>4</u><u>,</u><u>8</u><u>,</u><u>1</u><u>2</u><u>,</u><u>1</u><u>6</u>
<u>Step-by-Step </u><u>Explanation</u><u>:</u>
The given relation between the nth term and it's previous term is given by:
![\boxed{an = an - 1 + 4}](https://tex.z-dn.net/?f=%20%5Cboxed%7Ban%20%3D%20an%20-%201%20%2B%204%7D)
GiveN:
Now finding the other three terms of the AP with the given relation.
![a2 = a1 + 4](https://tex.z-dn.net/?f=a2%20%3D%20a1%20%2B%204)
Putting a1 = 4,
![a2 = 4 + 4 = 8](https://tex.z-dn.net/?f=a2%20%3D%20%204%20%2B%204%20%3D%208)
Now, Third term:
![a3 = a2 + 4](https://tex.z-dn.net/?f=a3%20%3D%20a2%20%2B%204)
Putting a2 = 8,
![a3 = 8 + 4 = 12](https://tex.z-dn.net/?f=a3%20%3D%208%20%2B%204%20%3D%2012)
Now, Fourth term:
![a4 = a3 + 4](https://tex.z-dn.net/?f=a4%20%3D%20a3%20%2B%204)
Putting a3 = 12,
![a4 = 12 + 4 = 16](https://tex.z-dn.net/?f=a4%20%3D%2012%20%2B%204%20%3D%2016)
Hence, The first four terms of the AP is 4, 8, 12 & 16.
Exponential growth because maths is good
Answer:
m<NQS = 32°
Step-by-step explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°
A Point is needed to define a circle
Hope this helps!!!
Answer:
hypotenuse:2 (AB)
adjacent side: 1 (AD)
opposite side:√3(BD)
Step-by-step explanation:
-->AB is hypotenuse cuz it's opposite to right angle (90°)
-->AD is adjacent,cuz it's adjacent to reference angle(60°)
-->BD is opposite side,cuz it's opposite to the reference angle(60°)
✌️:)