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BabaBlast [244]

3 years ago

14

Can you please help

1 answer:

Free_Kalibri [48]3 years ago

4 0

Answer:

The answer to the question provided is

$\frac{9}{5}$

Step-by-step explanation:

T

You might be interested in

Y + 12 = y + 10 + 2<br><br> how many solutions does the equation have

hjlf

Answer:

infinite

Step-by-step explanation:

8 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

Find a rational number and an irrational number that are between 5.2 and 5.5. Include the decimal approximation of the irrationa

mote1985 [20]

Answer:

5.3

Step-by-step explanation:

3 0

2 years ago

(+2) – (-6) what's the answer to this please write it out

harkovskaia [24]

Answer:

8

Step-by-step explanation:

+2-(-6)=2+6

the two negatives cancel each other out

2+6=8

3 0

3 years ago

Read 2 more answers

Help pleaseeee???!!!

jolli1 [7]

Answer:

h=8

Step-by-step explanation: $\frac{-7}{8} h= -7\\\\(\frac{8}{-7} )(\frac{-7}{8} h)= -7 (\frac{8}{-7} )\\\\\frac{-56}{-56}h = \frac{56}{7}\\\\ h=\frac{56}{7}\\\\h=8$

the goal is to isolate the variable, get it all by itself. to do that in this problem, we have to move the -7/8 away from the h. we do this by multiplying by the reciprocal (the opposite of the fraction). The reciprocal of -7/8 is 8/-7. So multiply both sides by this and you will get h=8

8 0

2 years ago