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kondor19780726 [428]
2 years ago
7

Why does the space station orbit the earth?

Physics
1 answer:
Anna35 [415]2 years ago
5 0
The purpose or how it orbits

The purpose is for future missions into space such as the moon, mars, or asteroids

It’s orbits due to being in low orbit of earth
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Suppose that we look at a photograph of many galaxies. Assuming that all galaxies formed at about the same time, which galaxy in
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D. The one that is closest to us
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Uniform solid disk rolls without slipping down a 19.0° inclined plane. what is the acceleration of the disk's center of mass?
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Below is the solution:

Let us say that the disk goes through a vertical elevation change of one meter. 

<span>The change in potential energy will equal the change in kinetic energy </span>

<span>PE = KEt + KEr </span>
<span>mgh = ½mv² + ½Iω² </span>

<span>for a uniform disk, the moment of inertia is </span>
<span>I = ½mr² </span>
<span>and </span>
<span>ω = v/r </span>

<span>mgh = ½mv² + ½(½mr²)(v/r)² </span>
<span>mgh = ½mv² + ¼mv² </span>
<span>gh = ¾v² </span>

<span>v² = 4gh/3 </span>

<span>v² = u² + 2as </span>

<span>if we assume initial velocity is zero </span>

<span>v² = 2as </span>
<span>a = v² / 2s </span>

<span>s(sinθ) = h </span>
<span>s = h/sinθ </span>

<span>a = 4gh/3 / 2(h/sinθ) </span>
<span>a = ⅔gsinθ </span>

<span>a = ⅔(9.8)sin25 </span>
<span>a = 2.8 m/s² </span>
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4 years ago
A 50-kg box is placed in the bed of a truck. the coefficient of static friction between the box and the truck bed is 0.54. if th
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3 years ago
A fast moving vehicle travelling at a speed of 25.4 m/s comes up behind another vehicle which is
ale4655 [162]

Answer:

     a = 6.1 m / s²

Explanation:

For this kinematics exercise, to solve the exercise we must set a reference system, we place it in the initial position of the fastest vehicle

Let's find the relative initial velocity of the two vehicles

          v₀ = v₀₂ - v₀₁

          v₀ = 25.4 - 13.6

          v₀ = 11.8 m / s

 

the fastest vehicle

          x = v₀ t + ½ a t²

The faster vehicle has an initial speed relative to the slower vehicle, therefore it is as if the slower vehicle were stopped, so the distance that must be traveled in a fast vehicle to reach this position is

          x = 11.4 m

         

let's use the expression

           v² = v₀² - 2 a x

how the vehicle stops v = 0

          a = v₀² / 2x

          a = \frac{11.8^2}{2 \ 11.4}

          a = 6.1 m / s²

this velocity is directed to the left

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While getting buff at the gym you lift a bunch of weights applying 1000N of force to lift them from the ground to a height of 2m
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